Suppose that we wish to evaluate the expression for the value This type of expression is called a radical expression because it contains the radical symbol Remember that means "the positive square root of the number "
To evaluate this expression at the given value, we replace with in the given expression and simplify.
Important: You may have heard somewhere that because and However, when we write down we always mean "the positive square root of ".
If we want the negative square root of , we write Sometimes, we want both, in which case we would write
Evaluate when
We replace with in the given expression, and simplify:
Evaluate $x(\sqrt{x}-1)$ when $x=9.$
|
a
|
$36$ |
|
b
|
$9$ |
|
c
|
$27$ |
|
d
|
$18$ |
|
e
|
$-18$ |
Evaluate $2\sqrt{2x} + 8$ when $x=18.$
|
a
|
$30$ |
|
b
|
$32$ |
|
c
|
$16$ |
|
d
|
$20$ |
|
e
|
$4$ |
Evaluate for
We replace with in the given expression, and simplify:
We can simplify even further using the product rule:
Evaluate $\sqrt{5x+4}$ for $x=8.$
|
a
|
$4\sqrt {11}$ |
|
b
|
$2\sqrt {11}$ |
|
c
|
$2\sqrt {22}$ |
|
d
|
$8\sqrt {11}$ |
|
e
|
$4\sqrt {22}$ |
Evaluate $\sqrt{7x-4}$ for $x=7.$
|
a
|
$3\sqrt {15}$ |
|
b
|
$3\sqrt 3$ |
|
c
|
$9\sqrt 5$ |
|
d
|
$3\sqrt 5$ |
|
e
|
$5\sqrt {3}$ |
Given that find
We replace with in the given expression, and simplify:
Given $f(x) = \dfrac{\sqrt{x}}{\sqrt{8-x}},$ find $f(6).$
|
a
|
$\sqrt{2}$ |
|
b
|
$1$ |
|
c
|
$2$ |
|
d
|
$\dfrac{1}{2}$ |
|
e
|
$\sqrt{3}$ |
Given $h(x) = \dfrac{\sqrt{x+6}}{\sqrt{x}},$ find $h(2).$
|
a
|
$6$ |
|
b
|
$2\sqrt{2}$ |
|
c
|
$2$ |
|
d
|
$4\sqrt{2}$ |
|
e
|
$8$ |
Evaluate at
We replace with in the given expression, and simplify as much as possible:
Evaluate $\sqrt[3]{x+3}$ at $x=5.$
|
a
|
$4$ |
|
b
|
$\sqrt{2}$ |
|
c
|
$2$ |
|
d
|
$1$ |
|
e
|
$3$ |
Evaluate $\sqrt[3]{7x+5}$ at $x=7.$
|
a
|
$9\sqrt[3]{2}$ |
|
b
|
$3\sqrt[3]{2}$ |
|
c
|
$18$ |
|
d
|
$3\sqrt[3]{6}$ |
|
e
|
$27\sqrt[3]{2}$ |