To divide square roots, we simply divide the numbers under the root. This is called the quotient rule for radicals.

To demonstrate, let's simplify the expression \dfrac{ \sqrt{10} }{ \sqrt{2} } by applying the quotient rule:

\dfrac{ \sqrt{10} }{ \sqrt{2} } = \sqrt{ \dfrac{10}{2} } = \sqrt{5}

The quotient rule also works for cube roots. For example,

\dfrac{ \sqrt[3]{10} }{ \sqrt[3]{2} } = \sqrt[3]{ \dfrac{10}{2} } = \sqrt[3]{5}

In general, the quotient rule works for any quotient of n th roots. So for any n, we have

\dfrac{ \sqrt[n]{10} }{ \sqrt[n]{2} } = \sqrt[n]{ \dfrac{10}{2} } = \sqrt[n]{5}.

Watch out! We cannot use the quotient rule when we have the quotient of different radicals, such as square roots and cube roots. For example, the expression \dfrac{ \sqrt{10} }{ \sqrt[3]{5} } cannot be simplified because the radicals \sqrt{\phantom{x}} and \sqrt[3]{\phantom{x}} are different.

FLAG

Express \sqrt{\dfrac{2}{7}} as the quotient of two radicals.

EXPLANATION

Applying the quotient rule, we have \sqrt{\dfrac{2}{7}}=\dfrac{\sqrt{2}}{\sqrt{7}} .

FLAG

$\sqrt{\dfrac{7}{4}} =$

a
$\dfrac{\sqrt{7}}{4}$
b
$\dfrac{\sqrt{7}}{\sqrt{2}}$
c
$\dfrac{7}{\sqrt{2}}$
d
$\dfrac{7}{2}$
e
$\dfrac{\sqrt{7}}{2}$

$\sqrt{\dfrac{3}{5}}=$

a
$\dfrac{\sqrt{3}}{15}$
b
$\dfrac{3}{\sqrt{5}}$
c
$\dfrac{\sqrt{3}}{5}$
d
$\dfrac{\sqrt{3}}{\sqrt{5}}$
e
$\dfrac{9}{\sqrt{5}}$

Express \dfrac{\sqrt{12}}{\sqrt{3}} as a single radical.

EXPLANATION

Using the quotient rule, we have \dfrac{\sqrt{12}}{\sqrt{3}} = \sqrt{\dfrac{12}{3}}= \sqrt{4} = 2 .

FLAG

$\dfrac{\sqrt{18}}{\sqrt{3}} =$

a
$ 3\sqrt{2}$
b
$ 2\sqrt{3}$
c
$ \sqrt{2}$
d
$ \sqrt{3}$
e
$ \sqrt{6}$

$\dfrac{\sqrt{5}}{\sqrt{2}} =$

a
$ \sqrt{\dfrac{25}{8}}$
b
$ \sqrt{\dfrac{5}{2}}$
c
$ \sqrt{\dfrac{25}{2}}$
d
$ \sqrt{\dfrac{5}{4}}$
e
$ \sqrt{10}$

Express \dfrac{\sqrt[3]{3}}{\sqrt[3]{4}} as a single radical.

EXPLANATION

Applying the quotient rule, we have \dfrac{\sqrt[3]{3}}{\sqrt[3]{4}} = \sqrt[3] {\dfrac{3}{4}} .

FLAG

$\dfrac{\sqrt[3]{81}}{\sqrt[3]{3}} =$

a
$3\sqrt[3]{3}$
b
$\dfrac{9}{\sqrt[3]{3}}$
c
$9\sqrt[3]{3}$
d
$3$
e
$9$

$\dfrac{\sqrt[3]{5}}{\sqrt[3]{7}} =$

a
$\sqrt[3]{\dfrac{5}{7}}$
b
$\sqrt[3]{\dfrac{25}{49}}$
c
$\sqrt[3]{35}$
d
$\dfrac{5}{\sqrt[3]7}$
e
$\dfrac{\sqrt[3]5}{7}$
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