To multiply square roots, we simply multiply the numbers under the root. This is called the product rule for radicals.
To demonstrate, let's simplify the expression by applying the product rule:
The product rule also works for cube roots. For example,
In general, the product rule works for any product of th roots. So for any we have
Watch out! We cannot use the product rule when we have the product of different radicals, such as square roots and cube roots. For example, the expression cannot be simplified because the radicals and are different.
The product rule can often be used to simplify square roots.
For example, consider Note that where is a perfect square. So, we have
Alternatively, if we're given a simplified square root and we want to convert it to the square root of a single number then we can work backwards using the product rule:
Simplify
Note that where is a perfect square. So, applying the product rule, we have
$\sqrt{50} =$
a
|
$20\sqrt{5}$ |
b
|
$25\sqrt{2}$ |
c
|
$2\sqrt{5}$ |
d
|
$10$ |
e
|
$5\sqrt{2}$ |
$\sqrt{21} =$
a
|
$9\cdot\sqrt{7}$ |
b
|
$3\sqrt{7}$ |
c
|
$49\sqrt{2}$ |
d
|
$7\sqrt{2}$ |
e
|
$\sqrt{3}\cdot\sqrt{7}$ |
Write as the square root of a single number.
Note that So, applying the product rule, we have
$2\sqrt{7}= $
a
|
$\sqrt{12}$ |
b
|
$\sqrt{28}$ |
c
|
$\sqrt{49}$ |
d
|
$\sqrt{14}$ |
e
|
$\sqrt{26}$ |
$\sqrt{3}\cdot\sqrt{2}= $
a
|
$\sqrt{6}$ |
b
|
$\sqrt{5}$ |
c
|
$6$ |
d
|
$3\sqrt{2}$ |
e
|
$2\sqrt{3}$ |
The product rule applies to cube roots as well.
For example, consider Note that where is a perfect cube. So, we have
Again, if we're given a simplified cube root and we want to convert it to the cube root of a single number then we can work backwards using the product rule:
Express as the cube root of a single number.
Using the product rule, we have
$\sqrt[3]{24} =$
a
|
$2\sqrt[3]{3}$ |
b
|
$4\sqrt[3]{3}$ |
c
|
$6$ |
d
|
$3\sqrt[3]{2}$ |
e
|
$8\sqrt[3]{3}$ |
$\sqrt[3]{3}\cdot\sqrt[3]{4}= $
a
|
$3$ |
b
|
$ 2\sqrt[3]{3}$ |
c
|
$ \sqrt[3]{12}$ |
d
|
$ \sqrt[3]{24}$ |
e
|
$ \sqrt[3]{6}$ |