We start by writing down the question using long division notation:

Next, we consider the hundreds and tens. Notice that $45$ goes ${\color{blue}2}$ times into ${\color{red}90}.$ Hence, we get:

Finally, notice that $45$ goes ${\color{blue}0}$ times into ${\color{red}2}.$ Hence, ${\color{red}2}$ is the remainder and we get:

We've gone through all the digits in the number $ 902,$ so the division is done. However, we still have a remainder of $2$, so we include this in our final answer.

Therefore, \[ 902 \div 45 = 20\,\text{R}\,2. \]

We start by writing down the question using long division notation:

Next, we consider the hundreds and tens. Notice that $34$ goes ${\color{blue}1}$ times into ${\color{red}40}.$ Hence, we get:

Finally, notice that $34$ goes ${\color{blue}2}$ times into ${\color{red}68}.$ Hence, we get:

We've gone through all the digits in the number $ 408,$ so the division is done.

Therefore, \[ 408 \div 34 = 12. \]

We start by writing down the question using long division notation:

Next, we consider the hundreds and tens. Notice that $15$ goes ${\color{blue}4}$ times into ${\color{red}73}.$ Hence, we get:

Finally, notice that $15$ goes ${\color{blue}8}$ times into ${\color{red}134}.$ Hence, we get:

We've gone through all the digits in the number $ 734,$ so the division is done.

Therefore, the remainder is $14.$

We start by writing down the question using long division notation:

Next, we consider the hundreds and tens. Notice that $32$ goes ${\color{blue}3}$ times into ${\color{red}96}.$ Hence, we get:

Finally, notice that $32$ goes ${\color{blue}0}$ times into ${\color{red}1}.$ Hence, ${\color{red}1}$ is the remainder and we get:

We've gone through all the digits in the number $ 961,$ so the division is done.

Therefore, the remainder is $1.$

To find out the number of candies the machine throws in one second, we need to divide $672$ by $48.$

We start by writing down the question using long division notation:

Next, we consider the hundreds and tens. Notice that $48$ goes ${\color{blue}1}$ times into ${\color{red}67}.$ Hence, we get:

Finally, notice that $48$ goes ${\color{blue}4}$ times into ${\color{red}192}.$ Hence, we get:

We've gone through all the digits in the number $ 672,$ so the division is done.

Therefore, \[ 672 \div 48 = 14. \] This means that the machine throws $14$ candies every second.

To find out the number of bags the store owner will need to pack all the sugar, we need to divide $495$ by $45.$

We start by writing down the question using long division notation:

Next, we consider the hundreds and tens. Notice that $45$ goes ${\color{blue}1}$ times into ${\color{red}49}.$ Hence, we get:

Finally, notice that $45$ goes ${\color{blue}1}$ times into ${\color{red}45}.$ Hence, we get:

We've gone through all the digits in the number $ 495,$ so the division is done.

Therefore, \[ 495 \div 45 = 11. \]

This means that the store owner will need a total of $11$ plastic bags to pack all the sugar.

We start by writing down the question using long division notation:

Since $81$ does not go into ${\color{red}72}$, we consider the hundreds, tens and ones altogether. Notice that $81$ goes ${\color{blue}9}$ times into ${\color{red}729}.$ Hence, we get:

We've gone through all the digits in the number $729$, so the division is done.

Therefore, \[ 729 \div 81 = 9. \]

We start by writing down the question using long division notation:

Since $57$ does not go into ${\color{red}39}$, we consider the hundreds, tens and ones altogether. Notice that $57$ goes ${\color{blue}7}$ times into ${\color{red}399}.$ Hence, we get:

We've gone through all the digits in the number $399$, so the division is done.

Therefore, \[ 399 \div 57 = 7. \]