To subtract $\dfrac{4}{\color{blue}{7}}$ from $2$, we need to express the whole number $2$ as an equivalent fraction with a denominator of ${\color{blue}{7}}.$

First, we write $2$ as an improper fraction:

\[ \dfrac 2 1 \]

Then, we put this fraction over a denominator of $\color{blue}7$ by multiplying the numerator and denominator by ${\color{blue}{7}}$:

\[ \dfrac{2\times {\color{blue}{7}}}{1\times{\color{blue}{7}}} = \dfrac{14}{7} \]

So now, we have to find:

\[ \dfrac{14}{7}-\dfrac{4}{7} \]

To subtract two fractions with like denominators, we subtract the numerators and keep the denominators the same. Therefore:

\begin{align*} \dfrac{14}{7}-\dfrac{4}{7} = \dfrac{14-4}{7}=\dfrac{10}{7} \end{align*}

To subtract $\dfrac{5}{\color{blue}{7}}$ from $1$, we need to express the whole number $1$ as an equivalent fraction with a denominator of ${\color{blue}{7}}.$

First, we write $1$ as an improper fraction:

\[ \dfrac{1}{1} \]

Then, we put this fraction over a denominator of $\color{blue}7$ by multiplying the numerator and denominator by ${\color{blue}{7}}$:

\[ \dfrac{1 \times {\color{blue}{7}}}{1\times{\color{blue}{7}}} = \dfrac{7}{7} \]

So now, we have to find:

\[ \dfrac{7}{7} - \dfrac{5}{7} \]

To subtract two fractions with like denominators, we subtract the numerators and keep the denominators the same. Therefore:

\begin{align*} \dfrac{7}{7} - \dfrac{5}{7} = \dfrac{7 - 5}{7} = \dfrac{2}{7} \end{align*}

To subtract $4$ from $\dfrac{17}{\color{blue}{3}}$, we need to express the whole number $4$ as an equivalent fraction with a denominator of ${\color{blue}{3}}.$

First, we write $4$ as an improper fraction:

\[ \dfrac 4 1 \]

Then, we put this fraction over a denominator of $\color{blue}3$ by multiplying the numerator and denominator by ${\color{blue}{3}}$:

\[ \dfrac{4\times {\color{blue}{3}}}{1\times{\color{blue}{3}}} = \dfrac{12}{3} \]

So now, we have to find:

\[ \dfrac{17}{3}-\dfrac{12}{3} \]

To subtract two fractions with like denominators, we subtract the numerators and keep the denominators the same. Therefore:

\begin{align*} \dfrac{17}{3}-\dfrac{12}{3} = \dfrac{17-12}{3}=\dfrac{5}{3} \end{align*}

Finally, we convert to a mixed number:

\[ 5\div 3 = 1\,\text{R}2 \]

So our final answer is $1\,\dfrac{2}{3}.$

To subtract $\dfrac{2}{\color{blue}{5}}$ from $3$, we need to express the whole number $3$ as an equivalent fraction with a denominator of ${\color{blue}{5}}.$

First, we write $3$ as an improper fraction:

\[ \dfrac 3 1 \]

Then, we put this fraction over a denominator of $\color{blue}5$ by multiplying the numerator and denominator by ${\color{blue}{5}}$:

\[ \dfrac{3\times {\color{blue}{5}}}{1\times{\color{blue}{5}}} = \dfrac{15}{5} \]

So now, we have to find:

\[ \dfrac{15}{5}-\dfrac{2}{5} \]

To subtract two fractions with like denominators, we subtract the numerators and keep the denominators the same. Therefore:

\begin{align*} \dfrac{15}{5}-\dfrac{2}{5} = \dfrac{15-2}{5}=\dfrac{13}{5} \end{align*}

Finally, we convert to a mixed number:

\[ 13\div 5 = 2\,\text{R}3 \]

So our final answer is $2\,\dfrac{3}{5}.$

To find out how many almonds they all ate, we must calculate the difference $3 - \dfrac{7}{5}.$

To subtract $\dfrac{7}{\color{blue}{5}}$ from $3$, we need to express the whole number $3$ as an equivalent fraction with a denominator of ${\color{blue}{5}}.$

First, we write $3$ as an improper fraction:

\[ \dfrac{3}{1} \]

Then, we put this fraction over a denominator of $\color{blue}5$ by multiplying the numerator and denominator by ${\color{blue}{5}}$:

\[ \dfrac{3 \times {\color{blue}{5}}}{1\times{\color{blue}{5}}} = \dfrac{15}{5} \]

So now, we have to find:

\[ \dfrac{15}{5} - \dfrac{7}{5} \]

To subtract two fractions with like denominators, we subtract the numerators and keep the denominators the same. Therefore:

\begin{align*} \dfrac{15}{5} - \dfrac{7}{5} = \dfrac{15 - 7}{5} = \dfrac{8}{5} \end{align*}

Finally, we convert to a mixed number:

\[ 8 \div 5 = 1 \, \textrm{R} \, 3 = 1 \, \dfrac{3}{5} \]

Therefore, George and his family ate $1 \, \dfrac{3}{5}$ kilograms of almonds.

To find the distance from the shop to the Zoo, we need to calculate the difference $4 - \dfrac{3}{8}.$

To subtract $\dfrac{3}{\color{blue}{8}}$ from $4$, we need to express the whole number $4$ as an equivalent fraction with a denominator of ${\color{blue}{8}}.$

First, we write $4$ as an improper fraction:

\[ \dfrac 4 1 \]

Then, we put this fraction over a denominator of $\color{blue}8$ by multiplying the numerator and denominator by ${\color{blue}{2}}$:

\[ \dfrac{4\times {\color{blue}{8}}}{1\times{\color{blue}{8}}} = \dfrac{32}{8} \]

So now, we have to find:

\[ \dfrac{32}{8}-\dfrac{3}{8} \]

To subtract two fractions with like denominators, we subtract the numerators and keep the denominators the same. Therefore:

\begin{align*} \dfrac{32}{8}-\dfrac{3}{8} = \dfrac{32-3}{8}=\dfrac{29}{8} \end{align*}

Finally, we convert to a mixed number:

\[ 29\div 8 = 3\,\text{R}5 \]

So our final answer is $3\,\dfrac{5}{8}$ miles.