It's straightforward to find the sum of a whole number and a proper fraction when we want the final answer to be a mixed number.

For instance, we can add 6 and \dfrac{1}{5} as follows: {\color{red}6} + {\color{blue}\dfrac{1}{5}} = {\color{red}6}\,{\color{blue}\dfrac{1}{5}}

Okay, that was pretty easy. And notice that we didn't need a fraction model to do it.

There are other ways to add whole numbers and fractions, which we'll discuss shortly. But first, let's see a few examples of this idea.

FLAG

8 + \dfrac{1}{4} is equivalent to which mixed number?

EXPLANATION

The number 8 is a whole number, and \dfrac{1}{4} is a proper fraction. Therefore, their sum is a mixed number:

8 + \dfrac{1}{4} = 8 \, \dfrac{1}{4}

FLAG

$12+\dfrac{1}{3}$ is equivalent to

a
$13\,\dfrac{1}{3}$
b
$12\,\dfrac{1}{3}$
c
$12\,\dfrac{2}{3}$
d
$\dfrac{12}{3}$
e
$\dfrac{17}{3}$

$\dfrac{2}{9}+6$ is equivalent to

a
$\dfrac{12}{15}$
b
$6\,\dfrac{2}{9}$
c
$\dfrac{8}{9}$
d
$\dfrac{2}{15}$
e
$2\,\dfrac{6}{9}$

Suppose that we want to add a whole number and a fraction. If we want the final answer to be an improper fraction, then we can proceed by turning the whole number into an improper fraction.

For example, let's find 2+\dfrac{1}{\color{blue}5} as an improper fraction.

We start by writing 2 as an improper fraction with 1 in the denominator: 2 =\dfrac{2}{1}

Then, we put this fraction over a denominator of \color{blue}5 by multiplying the numerator and denominator by {\color{blue}5} : \dfrac{2\times {\color{blue}{5}}}{1\times {\color{blue}{5}}} = \dfrac{10}{\color{blue}5}

Now, we can add the two numbers:

\begin{align*} 2 +\dfrac 1{\color{blue}5} = \underbrace{\dfrac{10}{\color{blue}5}}_{2} + \dfrac{1}{\color{blue}5} = \dfrac{11}{\color{blue}5} \end{align*}

And we're done!

To use some math jargon, we put the numbers 2 and \dfrac 1{\color{blue}5} over a common denominator of {\color{blue}5} before adding them.

Notice that this process is very similar to using fraction models.


To add 2 to \dfrac 1{\color{blue}5} using a model, we split each whole into {\color{blue}5} equal parts. When we do, we see that there are 11 shaded parts in total. So we arrive at the same answer:

2 +\dfrac{1}{\color{blue}5} = \dfrac{11}{{\color{blue}5}}

FLAG

Sophia walked \dfrac{5}{6} of a mile and then ran another 2 miles. Expressing the result as an improper fraction, how many miles did Sophia travel?

EXPLANATION

To find out how many miles Sophia traveled, we have to calculate the sum:

\dfrac{5}{6} + 2

To add \dfrac{5}{\color{blue}{6}} and 2 , we need to express the whole number 2 as an equivalent fraction with a denominator of {\color{blue}{6}}.

First, we write 2 as an improper fraction:

\dfrac{2}{1}

Then, we put this fraction over a denominator of \color{blue}6 by multiplying the numerator and denominator by {\color{blue}{6}} :

\dfrac{2 \times {\color{blue}{6}}}{1 \times{\color{blue}{6}}} = \dfrac{12}{6}

So now, we have to find the following sum:

\dfrac{5}{6} + \dfrac{12}{6}

To add two fractions with like denominators, we add the numerators and keep the denominators the same:

\begin{align*} \dfrac{5}{6} + \dfrac{12}{6} = \dfrac{5 + 12}{6} = \dfrac{17}{6} \end{align*}

Therefore, Sophia traveled \dfrac{17}{6} miles.

FLAG

What is $5+\dfrac{2}{3}$ written as an improper fraction?

a
$\dfrac{22}{3}$
b
$\dfrac{19}{3}$
c
$\dfrac{17}{3}$
d
$\dfrac{20}{3}$
e
$\dfrac{18}{3}$

What is $\dfrac{2}{5} + 13$ expressed as an improper fraction?

a
$\dfrac{76}{5}$
b
$\dfrac{61}{5}$
c
$\dfrac{67}{5}$
d
$\dfrac{71}{5}$
e
$\dfrac{7}{5}$

How do we write \dfrac{7}{\color{blue}4} + 5 as a mixed number?

Notice that we cannot write 5\,\dfrac 7 4 because \dfrac 7 4 is an improper fraction. Instead, let's find this sum using the same method as before.

First, we write 5 as an improper fraction:

\dfrac{5}{1}

Then, we put this fraction over a denominator of \color{blue}4 by multiplying the numerator and denominator by {\color{blue}{4}} :

\dfrac{5 \times {\color{blue}{4}}}{1 \times{\color{blue}{4}}} = \dfrac{20}{4}

So now, we have to find the following sum:

\dfrac{7}{4} + \dfrac{20}{4}

To add two fractions with like denominators, we add the numerators and keep the denominators the same:

\begin{align*} \dfrac{7}{4} + \dfrac{20}{4} = \dfrac{7 + 20}{4} = \dfrac{27}{4} \end{align*}

Finally, we convert this to a mixed number:

27 \div 4 = 6 \, \textrm{R} \, 3 = 6 \, \dfrac{3}{4}

FLAG

Tom and Margaret went to a fruit store to buy apples and pears. Tom bought 3 kilograms of apples while Margaret bought \dfrac{11}{3} kilograms of pears. Expressing the result as a mixed number, how many kilograms of fruit did they buy together?

EXPLANATION

To know how many kilograms they bought, we have to calculate the sum:

3 + \dfrac{11}{3}

To add 3 + \dfrac{11}{\color{blue}{3}} , we need to express the whole number 3 as an equivalent fraction with a denominator of {\color{blue}{3}}.

First, we write 3 as an improper fraction:

\dfrac{3}{1}

Then, we put this fraction over a denominator of \color{blue}3 by multiplying the numerator and denominator by {\color{blue}{3}} :

\dfrac{3 \times {\color{blue}{3}}}{1 \times{\color{blue}{3}}} = \dfrac{9}{3}

So now, we have to find the following sum:

\dfrac{9}{3} + \dfrac{11}{3}

To add two fractions with like denominators, we add the numerators and keep the denominators the same.

\begin{align*} \dfrac{9}{3} + \dfrac{11}{3} = \dfrac{9 + 11}{3} = \dfrac{20}{3} \end{align*}

Finally, we convert this to a mixed number:

20 \div 3 = 6 \, \textrm{R} \, 2 = 6 \, \dfrac{2}{3}

Thus, Tom and Margaret bought 6 \, \dfrac{2}{3} kilograms of fruit.

FLAG

What is $\dfrac{7}{4}+3$ expressed as an improper fraction?

a
$\dfrac{19}{4}$
b
$\dfrac{23}{4}$
c
$\dfrac{21}{4}$
d
$\dfrac{17}{4}$
e
$\dfrac{25}{4}$

What is $8 + \dfrac{4}{3}$ expressed as a mixed number?

a
$9 \, \dfrac{2}{3}$
b
$8 \, \dfrac{3}{4}$
c
$9 \, \dfrac{1}{3}$
d
$10 \, \dfrac{4}{5}$
e
$10 \, \dfrac{3}{4}$
Flag Content
Did you notice an error, or do you simply believe that something could be improved? Please explain below.
SUBMIT
CANCEL