To simplify a rational expression, we cancel out the largest common factor from the numerator and denominator. To do this, we sometimes need to factor the numerator and denominator before canceling.

For example, suppose that we wish to simplify \dfrac {4x - 12} {10x + 4}. To do this, we factor the numerator and denominator and cancel any factors that they have in common.

\eqalign{ \dfrac {4x - 12} {10x + 4} &=\dfrac {4(x - 3)} {2(5x + 2)}\\[5pt] &=\dfrac {2 \cdot 2 \cdot (x - 3)} {2(5x + 2)}\\[5pt] &=\dfrac {\cancel{2} \cdot 2(x - 3)} {\cancel{2}(5x + 2)}\\[5pt] &=\dfrac {2(x - 3)} {5x + 2} }

FLAG

What is \dfrac {2x + 4} {2} reduced to lowest terms?

EXPLANATION

We factor the numerator and denominator and cancel any factors that they have in common.

\begin{eqnarray} \require{cancel} \eqalign{ \dfrac {2x + 4} {2} &= \dfrac {2(x + 2)} {2} \\[5pt] &= \dfrac {\cancel{2}(x + 2)} {\cancel{2} \cdot 1} \\[5pt] &= \dfrac {x + 2 } {1} \\[5pt] &= x + 2 } \end{eqnarray}

FLAG

What is $\dfrac{4z - 8x} {2z - 4y}$ reduced to its lowest terms?

a
$\dfrac{2(z - 2x)} {z - 2y}$
b
$4$
c
$\dfrac{z - 2x} {z - 2y}$
d
$\dfrac{z + 2x} {z + 2y}$
e
$2$

$\dfrac {6b+6a} {6a}=$

a
$b+a$
b
$6b$
c
$\dfrac {b+a} {a}$
d
$b+1$
e
$b$

Simplify the expression \dfrac {6y + 2} {3xy + x}.

EXPLANATION

We factor the numerator and denominator and cancel any factors that they have in common. \require{cancel} \eqalign{ \dfrac {6y + 2} {3xy + x} &= \dfrac {6y + 2} {x(3y + 1)} \\[5pt] &=\dfrac {2(3y + 1)} {x(3y + 1)} \\[5pt] &=\dfrac {2\cancel{(3y + 1)} } {x \cancel{(3y + 1)} } \\[5pt] &=\dfrac {2 } {x} }

FLAG

$\dfrac{4xy - x} {4y - 1}=$

a
$\dfrac{x}{y}$
b
Not reducible
c
$\dfrac{1}{y}$
d
$xy$
e
$x$

$\dfrac{ab - b} {3a - 3}=$

a
$\dfrac{b}{a}$
b
Not reducible
c
$\dfrac{b}{3}$
d
$\dfrac{a}{b}$
e
$\dfrac{3}{b}$

What is \dfrac{x+2}{2x} reduced to lowest terms?

EXPLANATION

The numerator and denominator have no common factors, so the expression can not be reduced. The expression \dfrac{x+2}{2x} is already in lowest terms.

FLAG

$\dfrac {7x + 1} {7x}=$

a
$1$
b
$7x + 1$
c
$\dfrac {7x + 1} {7x}$
d
$7x$
e
$7$

$\dfrac {3a+4} {2}=$

a
$2$
b
$3a+2$
c
$3a+4$
d
$\dfrac{3a}{2}$
e
$\dfrac {3a+4} {2}$

Simplify \dfrac{5c + 10p - 20}{5p+15}.

EXPLANATION

We factor the numerator and denominator and cancel any factors that they have in common. \require{cancel} \begin{align*} \dfrac{5c + 10p - 20}{5p+15} &= \dfrac{5(c+2p-4)}{5(p+3)} \\[5pt] &= \dfrac{\cancel{5}(c+2p-4)}{\cancel{5}(p+3)} \\[5pt] &= \dfrac{c+2p-4}{p+3} \end{align*}

FLAG

What is $\dfrac{4ab-8+10x}{10x+8-2ab}$ reduced to its lowest terms?

a
$-2$
b
$\dfrac{2ab-4+5x}{5x+4-ab}$
c
$2$
d
$\dfrac{ab-2+5x}{5x+2-ab}$
e
$\dfrac{ab-4+5x}{5x+4-ab}$

What is $\dfrac{8a-4b+12}{20b+ 8a}$ reduced to its lowest terms?

a
$\dfrac{-4b+12}{20b}$
b
$\dfrac{-b+5}{4b}$
c
$\dfrac{2a-b}{5b+2a}$
d
$\dfrac{2a+b-3}{5b-2a}$
e
$\dfrac{2a-b+3}{5b+2a}$
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