Factoring is the opposite of distributing. To illustrate, consider the expression 4(a-2b). If you consider distributing as going forward, \begin{align*} 4(a-2b) &=\\ 4 \cdot a - 4 \cdot 2b &= \\ 4a - 8b, \end{align*} then factoring would be going in reverse: \begin{align*} 4a-8b &=\\ ({\color{red}4} \cdot {\color{blue}a}) \;{\color{blue}-}\; ({\color{red}4} \cdot {\color{blue}2b}) &= \\ {\color{red}4} \; ({\color{blue}a - 2b}) & \end{align*}

In this case, you would say that \color{red}4 was factored out of 4a-8b.

To factor any expression, we just need to follow these two steps:

  1. Separate the greatest common factor from each of the terms (ignoring any negative signs). In this case, \textrm{GCF}(4a,8b) = {\color{red}{4}}, so: \begin{align*} 4a-8b &= \\ ({\color{red}{4}} \cdot a) - ({\color{red}{4}} \cdot 2b)& \end{align*}
  2. Place the common factor in front of the parentheses, leaving whatever remains inside the parentheses: \begin{align*} ({\color{red}{4}} \cdot a) - ({\color{red}{4}} \cdot 2b) &= \\ {\color{red}{4}}(a-2b)& \end{align*}
FLAG

Factor the following expression: 6a+30.

EXPLANATION

We factor in two steps:

  1. Separate the greatest common factor from each of the terms. In this case, \textrm{GCF}(6a,30) = 6, so: \begin{align*} 6a+30 &= \\ (6\cdot a)+(6\cdot5)& \end{align*}
  2. Place the common factor in front of the parentheses, leaving whatever remains inside the parentheses: \begin{align*} (6\cdot a)+(6\cdot5) &= \\ 6(a+5)& \end{align*}

Thus, the factored form of the expression is 6(a+5).

FLAG

Factor $3x+12.$

a
$3(x+3)$
b
$3(x+12)$
c
$4(x+3)$
d
$15x$
e
$3(x+4)$

Factor the expression $8a+24.$

a
$8(a+12)$
b
$8(a+3)$
c
$8(a+4)$
d
$12a$
e
$3(a+8)$

Factor the expression $30y-36.$

a
$6(6y-5)$
b
$2(15y+18)$
c
$3(10y-13)$
d
$6(5y-6)$
e
$10(3y-4)$

When the terms of an expression are negative, we can also factor out a negative sign. For example, the expression -x-1 can be factored into -(x+1).

By the same token, the expression -2x-2 can be factored by first factoring out a negative sign, and then factoring out the greatest common factor of 2{:} \begin{align*} -2x-2 &= \\[5pt] -(2x+2) &= \\[5pt] -2(x+1) & \end{align*}

FLAG

Factor the following expression: -5a-35.

EXPLANATION

Both terms are negative, so we begin by factoring out a negative sign:

\begin{align*} -5a-35 &= \\ -(5a+35)& \end{align*}

Then, we continue factoring in two steps:

  1. Separate the greatest common factor from each of the terms. In this case, \textrm{GCF}(5a,35) = 5, so \begin{align*} -(5a + 35) &= \\ -( 5 \cdot a + 5 \cdot 7)& \end{align*}
  2. Place the common factor in front of the parentheses, leaving whatever remains inside the parentheses: \begin{align*} -(5 \cdot a + 5 \cdot 7) &= \\ -5(a+7)& \end{align*}

Thus, the factored form of the expression is -5(a+7).

FLAG

Factor $-36a-3.$

a
$3(a-12)$
b
$-3(12a+1)$
c
$3(12a+1)$
d
$3(12a-1)$
e
$-3(a-12)$

Factor $-20a-28b.$

a
$4(5a+7b)$
b
$-4(-5a-7b)$
c
$-4(5a-7b)$
d
$-4(-5a+7b)$
e
$-4(5a+7b)$

Factor $-42m-54n.$

a
$-6(7m-9n)$
b
$-6(7m+9n)$
c
$6(9m-7n)$
d
$-6(9m+7n)$
e
$6(7m-9n)$

Factor the expression 27a+33b-30.

EXPLANATION

We factor in two steps:

  1. Separate the greatest common factor from each of the terms (ignoring any negative signs). In this case, \textrm{GCF}(27a, 33b, 30) = 3, so: \begin{align*} 27a+33b-30 &= \\ 3 \cdot 9a + 3 \cdot 11b - 3 \cdot 10 & \end{align*}
  2. Place the common factor in front of the parentheses, leaving whatever remains inside the parentheses: \begin{align*} 3 \cdot 9a + 3 \cdot 11b - 3 \cdot 10&= \\ 3(9a+11b-10)& \end{align*}

Thus, the factored form of the expression is 3(9a+11b-10).

FLAG

Factor $15p - 9q +21.$

a
$3(5p-3q+7)$
b
$5(3p-9q+3)$
c
$5(3p-3q+7)$
d
$3(5p+3q-9)$
e
$3(5q-3p)$

Factor $24x + 40y - 72.$

a
$ 8(3x-5y-7)$
b
$ 8(3x+5y-9)$
c
$ 8(4x-5y-9)$
d
$ 8(4x-5y-7)$
e
$ 8(3x-10y-7)$

Factor $18x + 6y - 12.$

a
$2(9x-3y+6)$
b
$4(4x+y-3)$
c
$5(4x+y-2)$
d
$3(6x+2y+4)$
e
$6(3x+y-2)$
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