First, we remove the parentheses by distributing the negative sign. This gives

\[ 5 - x - 1. \]

Finally, we collect like terms:

\begin{align*} 5 - x - 1 &=\\[5pt] (5-1) - x &=\\[5pt] 4-x& \end{align*}

First, we remove the parentheses by distributing the negative sign. This gives

\[ -6 - 2x - 4. \]

Finally, we collect like terms:

\begin{align*} -6 - 2x - 4 &=\\[5pt] (-6-4) - 2x &=\\[5pt] -10-2x& \end{align*}

First, we remove the parentheses by distributing the negative sign. This gives

\[ 4-2h + 3 \]

Finally, we collect like terms:

\begin{align*} 4-2h + 3 &=\\[5pt] (4+3) - 2h &=\\[5pt] 7-2h& \end{align*}

First, we remove the parentheses by distributing the negative sign. This gives

\[ -3h-2h + 9. \]

Finally, we collect like terms:

\begin{align*} -3h-2h + 9 &=\\[5pt] (-3h-2h) +9 &=\\[5pt] -5h+9& \end{align*}

Notice that the expression we need to subtract from $5$ must be expanded using the distributive law.

So first, let's write some big brackets around the expression in parentheses, keeping the minus sign outside.

\[ 5 - \Big[3(x+1)\Big] \]

Next, we expand the expression inside the brackets using the distributive law. This gives

\[ 5 - \Big[3x+3\Big]. \]

Now, we remove the brackets by distributing the negative sign. This gives

\[ 5 - 3x - 3. \]

Finally, we collect like terms:

\begin{align*} 5 - 3x - 3 &=\\[5pt] (5-3) - 3x &=\\[5pt] 2-3x & \end{align*}

Notice that the expression we need to subtract from $-6$ must be expanded using the distributive law.

So first, let's write some big brackets around the expression in parentheses, keeping the minus sign outside.

\[ -6 - \Big[2(3t+5)\Big] \]

Next, we expand the expression inside the brackets using the distributive law. This gives

\[ -6 - \Big[6t+10\Big]. \]

Now, we remove the brackets by distributing the negative sign. This gives

\[ -6 - 6t - 10. \]

Finally, we collect like terms:

\begin{align*} -6 - 6t - 10 &=\\[5pt] (-6-10) - 6t &=\\[5pt] -16-6t & \end{align*}

Notice that the expression we need to subtract from $4$ must be expanded using the distributive law.

So first, let's write some big brackets around the expression in parentheses, keeping the minus sign outside.

\[ 4 - \Big[6(2h-3)\Big] \]

Next, we expand the expression inside the brackets using the distributive law. This gives

\[ 4 - \Big[12h-18\Big]. \]

Now, we remove the brackets by distributing the negative sign. This gives

\[ 4 - 12h + 18. \]

Finally, we collect like terms:

\begin{align*} 4 - 12h + 18 &=\\[5pt] (4+18) - 12h &=\\[5pt] 22-12h & \end{align*}

Notice that the expression we need to subtract from $-1$ must be expanded using the distributive law.

So first, let's write some big brackets around the expression in parentheses, keeping the minus sign outside.

\[ -1 - \Big[5(2v-1)\Big] \]

Next, we expand the expression inside the brackets using the distributive law. This gives

\[ -1 - \Big[10v-5\Big]. \]

Now, we remove the brackets by distributing the negative sign. This gives

\[ -1 - 10v + 5. \]

Finally, we collect like terms:

\begin{align*} -1 - 10v + 5 &=\\[5pt] (-1+5) - 10v &=\\[5pt] 4-10v & \end{align*}