So far, we know the following:

  • To find the square root of a number, we need to find another that multiplies by itself 2 times to give the original number. For example, \sqrt{9} = \sqrt{3 \cdot 3} = \sqrt{3^2} = 3.

  • To find the cube root of a number, we need to find another that multiplies by itself 3 times to give the original number. For example, \sqrt[3]{8} = \sqrt[3]{2 \cdot 2 \cdot 2} = \sqrt[3]{2^3} = 2.

We can extend this to any root. In general, to find the n th root of a number, we needed to find another number that multiplies by itself n times to give the original number. We express the n th root as the radical \sqrt[n]{\phantom{0}}. For instance,

\sqrt[{\color{blue}4}]{16} = \sqrt[{\color{blue}4}]{\underbrace{2\cdot 2\cdot 2\cdot 2}_{{\color{blue}4}\text{ times}}} = \sqrt[{\color{blue}4}]{2^4} = 2.

Given a radical \sqrt[n]{x}, we can write an equivalent expression using the fractional exponent x^{1/n}. To demonstrate, let's write an equivalent expression for \sqrt[7]{3}.

Comparing \sqrt[n]{x} with \sqrt[7]{3}, we get x = 3 and n = 7. Therefore,

\sqrt[7]{3} = 3^{1/7}.

The reverse is also true: the fractional exponent x^{1/n} can be written as the radical \sqrt[n]{x}.

Note: Remember that the square root of a number corresponds to the case of n=2. So, for example, we have \sqrt{3} = 3^{1/2}.

FLAG

Write 8^{1/5} using radical notation.

EXPLANATION

The fractional exponent x^{1/n} can be written as the radical \sqrt[n]{x}.

Comparing x^{1/n} with 8^{1/5}, we get x = 8 and n = 5. Therefore, 8^{1/5} = \sqrt[5]{8}.

FLAG

Write $6^{1/4}$ using radical notation.

a
$\sqrt[4]{\dfrac 16}$
b
$\sqrt{6^4}$
c
$\sqrt[4]{6}$
d
$\sqrt[6]{4}$
e
$\sqrt[6]{\dfrac 14}$

Write $5^{1/5}$ using radical notation.

a
$5^5$
b
$\sqrt[5]{5}$
c
$1$
d
$\dfrac{1}{5^5}$
e
$\sqrt[5]{\dfrac{1}{5}}$

Express \sqrt[5]{4} using a fractional exponent.

EXPLANATION

The radical \sqrt[n]{x} can be written using a fractional exponent as x^{1/n}.

Comparing \sqrt[n]{x} with \sqrt[5]{4}, we get x = 4 and n = 5. Therefore,

\sqrt[5]{4} = 4^{1/5}.

FLAG

$\sqrt[7]{2} = $

a
$1^{2/7}$
b
$7^{1/2}$
c
$2^{1/7}$
d
$7^{2/1}$
e
$2^{7/1}$

$\sqrt{10} = $

a
$2^{{10}/1}$
b
$5$
c
$10^{2/1}$
d
$10^{1/2}$
e
$2^{1/{10}}$

Write 5^{2/3} using radical notation.

EXPLANATION

First, using the power law for exponents, we can write our expression as 5^{2/3} = 5^{2\cdot (1/3)} = \left(5^2\right)^{1/3}.

The fractional exponent x^{1/n} can be written as the radical \sqrt[n]{x}.

Comparing x^{1/n} with our expression above, we get x = 5^2 and n = 3. Therefore, \left(5^2\right)^{1/3} = \sqrt[3]{5^2}.

FLAG

$4^{7/6} = $

a
$\sqrt[4]{7^6}$
b
$\sqrt[7]{4^6}$
c
$\sqrt[6]{7^4}$
d
$\sqrt[7]{6^4}$
e
$\sqrt[6]{4^7}$

$2^{4/3} = $

a
$\sqrt[3]{16}$
b
$\sqrt[4]{9}$
c
$\sqrt{27}$
d
$\sqrt[3]{48}$
e
$\sqrt[4]{8}$

Express \sqrt[3]{4^2} using a fractional exponent.

EXPLANATION

The radical \sqrt[n]{x} can be written using a fractional exponent as x^{1/n}.

Comparing \sqrt[n]{x} with \sqrt[3]{4^2}, we get x = 4^2 and n = 3. Therefore, \sqrt[3]{4^2} = \left(4^2\right)^{1/3}.

Finally, using the power law for exponents, we have \left(4^2\right)^{1/3} = 4^{2/3}.

FLAG

$\sqrt[4]{3^5} = $

a
$3^{5/4}$
b
$5^{4/3}$
c
$3^{4/5}$
d
$4^{3/5}$
e
$5^{3/4}$

$\sqrt{4^3} = $

a
$2^{3/4}$
b
$4^{3/2}$
c
$2^{4/3}$
d
$3^{2/4}$
e
$4^{2/3}$
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