We know how to evaluate expressions like 2^3, 2^2, 2^1 , and even 2^0. But what if the power is negative? How would we evaluate 2^{-1}, for example?

To help us with that, let's go back to the results table for powers of 2.

\begin{align*} 2^{\color{red}{4}} &= {\color{blue}{16}}\\ 2^{\color{red}{3}} &= {\color{blue}{8}}\\ 2^{\color{red}{2}} &= {\color{blue}{4}}\\ 2^{\color{red}{1}} &= {\color{blue}{2}}\\ 2^{\color{red}{0}} &= {\color{blue}{1}}\\ 2^{\color{red}{-1}} &= {\color{blue}{\square}}\,? \end{align*}

As we go down the list, the number in blue is divided by 2 every time. If we follow the same pattern, we find that 2^{\color{red}{-1}} = {\color{blue}{1}}\div 2 = \dfrac{1}{2}.

Now, \dfrac{1}{2} is just the reciprocal of 2. So, raising a number to the power of -1 is the same as finding its reciprocal!

FLAG

Express 3^{-1} as a fraction in its simplest form.

EXPLANATION

The expression 3^{-1} means the reciprocal of 3 . Hence

3^{-1} = \dfrac{1}{3}.

FLAG

$7^{-1}=$

a
$-\dfrac{1}{7}$
b
$(-7)^1$
c
$-1$
d
$\dfrac{1}{7}$
e
$\dfrac{7}{1}$

$11^{-1}=$

a
$11$
b
$\dfrac{1}{11}$
c
$-11$
d
$-\dfrac{1}{11}$
e
$1$

What is (-4)^{-1}?

EXPLANATION

The expression (-4)^{-1} means the reciprocal of -4. Therefore,

(-4)^{-1} = -\dfrac{1}{4}.

FLAG

What is $(-3)^{-1}?$

a
$-1$
b
${-3}$
c
$-\dfrac {1} {3}$
d
$\dfrac {1} {3}$
e
${3}$

What is $(-10)^{-1}?$

a
$-10$
b
$-1$
c
$-\dfrac{1}{10}$
d
$\dfrac{1}{10}$
e
$10$

Evaluate \left(\dfrac{2}{3}\right)^{-1}.

EXPLANATION

The expression \left(\dfrac{2}{3}\right)^{-1} means the reciprocal of \dfrac{2}{3}. Therefore,

\left(\dfrac{2}{3}\right)^{-1} = \dfrac{3}{2}.

FLAG

$\left(\dfrac{3}{2}\right)^{-1}=$

a
$\dfrac{1}{3}$
b
$-\dfrac{1}{3}$
c
$-\dfrac{3}{2}$
d
$-\dfrac{2}{3}$
e
$\dfrac{2}{3}$

$\left(\dfrac{4}{5}\right)^{-1}=$

a
$\dfrac{3}{4}$
b
$-\dfrac{4}{3}$
c
$-\dfrac{4}{5}$
d
$\dfrac{5}{4}$
e
$\dfrac{4}{5}$
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