We start with the given multiplication problem: \[ 40 \times 5 = {\color{blue}{200}} \]

We can find the correct answer for $42 \times 5$ using repeated addition: \begin{align*} 41 \times 5 & = {\color{blue}{200}} + 5 = {\color{red}{205}}\\[10pt] 42 \times 5 & = {\color{red}{205}} + 5 = 210 \end{align*}

Therefore, $42 \times 5 = 210.$

We start with the given multiplication problem:

\[ 30\times 3 = {\color{blue}{90}} \]

We can find the correct answer for $33\times 3$ using repeated addition:

\begin{align*} 31\times 3 &= {\color{blue}{90}} + 3 ={\color{red}{93}}\\[10pt] 32\times 3 &= {\color{red}{93}} + 3 ={\color{purple}{96}} \\[10pt] 33\times 3 &= {\color{purple}{96}} + 3 =99 \\[10pt] \end{align*}

Therefore, $33\times 3 = 99.$

We start with the given multiplication problem: \[ 90 \times 5 = {\color{blue}{450}} \]

We can find the correct answer for $94 \times 5$ using repeated addition: \begin{align*} 91 \times 5 & = {\color{blue}{450}} + 5 = {\color{red}{455}}\\[10pt] 92 \times 5 & = {\color{red}{455}} + 5 = {\color{purple}{460}} \\[10pt] 93 \times 5 & = {\color{purple}{460}} + 5 = {\color{magenta}{465}} \\[10pt] 94 \times 5 & = {\color{magenta}{465}} + 5 = 470 \end{align*}

Therefore, $94 \times 5 = \bbox[3pt, Gainsboro]{\color{blue}470}.$

We start with the given multiplication problem: \[ 300 \times 6 = {\color{blue}{1,800}} \]

We can find the correct answer for $302 \times 6$ using repeated addition: \begin{align*} 301 \times 6 & = {\color{blue}{1,800}} + 6 = {\color{red}{1,806}}\\[10pt] 302 \times 6 & = {\color{red}{1,806}} + 6 = 1,812 \end{align*}

Therefore, $302 \times 6 = 1,812.$

We start with the given multiplication problem: \[ 300 \times 9 = {\color{blue}{2,700}} \]

We can find the correct answer for $303 \times 9$ using repeated addition: \begin{align*} 301 \times 9 &= {\color{blue}{2,700}} + 9 ={\color{red}{2,709}}\\[10pt] 302 \times 9 &= {\color{red}{2,709}} + 9 ={\color{purple}{2,718}} \\[10pt] 303 \times 9 &= {\color{purple}{2,718}} + 9 = 2,727 \end{align*}

Therefore, $303 \times 9 = \bbox[3pt, Gainsboro]{\color{blue}2,727}.$

We start with the given multiplication problem: \[ 250 \times 3 = {\color{blue}{750}} \]

We can find the correct answer for $254 \times 3$ using repeated addition: \begin{align*} 251 \times 3 & = {\color{blue}{750}} + 3 ={\color{red}{753}}\\[10pt] 252 \times 3 & = {\color{red}{753}} + 3 = {\color{purple}{756}} \\[10pt] 253 \times 3 & = {\color{purple}{756}} + 3 = {\color{magenta}759}\\[10pt] 254 \times 3 & = {\color{magenta}{759}} + 3 = 762 \end{align*}

Therefore, $254 \times 3 = \bbox[3pt, Gainsboro]{\color{blue}762}.$

We start with the given multiplication problem: \[ 2,000 \times 8 = {\color{blue}{16,000}} \]

We can find the correct answer for $2,002 \times 8$ using repeated addition: \begin{align*} 2,001 \times 8 & = {\color{blue}{16,000}} + 8 = {\color{red}{16,008}}\\[10pt] 2,002 \times 8 & = {\color{red}{16,008}} + 8 = 16,016 \end{align*}

Therefore, $2,002 \times 8 = \bbox[3pt, Gainsboro]{\color{blue}16,016}.$

We start with the given multiplication problem: \[ 1,000 \times 8 = {\color{blue}{8,000}} \]

We can find the correct answer for $1,003 \times 8$ using repeated addition: \begin{align*} 1,001 \times 8 & = {\color{blue}{8,000}} + 8 = {\color{red}{8,008}}\\[10pt] 1,002 \times 8 & = {\color{red}{8,008}} + 8 = {\color{purple}{8,016}} \\[10pt] 1,003 \times 8 & = {\color{purple}{8,016}} + 8 = 8,024 \end{align*}

Therefore, $1,003 \times 8 = 8,024.$

We start with the given multiplication problem: \[ 3,200 \times 3 = {\color{blue}{9,600}} \]

We can find the correct answer for $3,204 \times 3$ using repeated addition: \begin{align*} 3,201 \times 3 & = {\color{blue}{9,600}} + 3 ={\color{red}{9,603}}\\[10pt] 3,202 \times 3 &= {\color{red}{9,603}} + 3 ={\color{purple}{9,606}} \\[10pt] 3,203 \times 3 &= {\color{purple}{9,606}} + 3 ={\color{magenta}{9,609}} \\[10pt] 3,204 \times 3 &= {\color{magenta}{9,609}} + 3 = 9,612 \end{align*}

Therefore, $3,204 \times 3 = \bbox[3pt, Gainsboro]{\color{blue}9,612}.$