When we multiply two negative numbers, the answer is always a positive number.

As an example, let's calculate the product

(-2) \cdot (-8).

Here, we have a product of two negative numbers, \color{red}-2 and {\color{red}-8}. The product will be positive. You can think of it as though the two minus signs cancel each other out: \begin{align*} \mathbf{\color{red}(-)} \:\mathbf{\cdot}\: \mathbf{\color{red}(-)} \:=\: \mathbf{\color{blue}(+)} \end{align*}

So we have {\color{red}(-2)} \cdot {\color{red}(-8)} = {\color{blue} \fbox{[math]\phantom{16}[/math]} }. Now, to compute the number in the box, we multiply 2 by 8 without any signs: 2 \cdot 8 = 16 . Therefore, {\color{red}(-2)} \cdot {\color{red}(-8)} = {\color{blue} 16}.

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Calculate (-9 ) \cdot (-5).

EXPLANATION

We have a product of two negative numbers, \color{red}-9 and {\color{red}-5}. So the product will be positive: {\color{red}(-9)} \cdot {\color{red}(-5)} = {\color{blue}\fbox{[math]\phantom{45}[/math]}} Now, to compute the number that goes in the box, we multiply 9 and 5 without any signs: 9 \cdot 5 = 45. So, we get {\color{red}(-9)} \cdot {\color{red}(-5)} = {\color{blue}45}.

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$(-2) \cdot (-5)=$

a
$25$
b
$7$
c
$-10$
d
$-7$
e
$10$

$(-12) \cdot (-3)=$

a
$24$
b
$36$
c
$15$
d
$-15$
e
$-36$

What is the value of (-3) \cdot (-5) \cdot (-10)?

EXPLANATION

Let's start by multiplying the first two numbers. We have the product of two negatives, which gives a positive: {\color{red}(-3)} \cdot {\color{red}(-5)} = {\color{blue}15}. So we now have

\underbrace{{\color{red}(-3)} \cdot {\color{red}(-5)}}_{\large {\color{blue}15}} \cdot {\color{red}(-10)} = {\color{blue}15} \cdot {\color{red}(-10)}.

Then, we work out this remaining product using the fact that a positive times a negative gives a negative:

{\color{blue}15} \cdot {\color{red}(-10)} = {\color{red}-(15\cdot 10)} = {\color{red}-150}

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$(-8) \cdot4 \cdot1=$

a
$32$
b
$-24$
c
$24$
d
$-32$
e
$-36$

$(-2) \cdot(-5) \cdot(- 4)=$

a
$40$
b
$-50$
c
$60$
d
$-40$
e
$50$

Calculate \left(-\dfrac{1}{2}\right) \cdot \left(-\dfrac{10}{3}\right).

EXPLANATION

We have a product of two negative numbers, so the product will be positive, and we can drop the minus signs as follows: \begin{align*} \require{cancel} \left(-\dfrac{1}{2}\right) \cdot \left(-\dfrac{10}{3}\right) &= \dfrac{1}{2} \cdot \dfrac{10}{3} \end{align*}

Now, we multiply the fractions by multiplying the numerators and denominators separately:

\begin{align*} \require{cancel} \dfrac{1}{2} \cdot \dfrac{10}{3} &= \dfrac{1 \cdot 10}{2 \cdot 3} \\[5pt] &= \dfrac{5 \cdot 2}{2 \cdot 3} \\[5pt] &= \dfrac{5 \cdot \cancel{2}}{\cancel{2} \cdot 3} \\[5pt] &= \dfrac{5}{3} \end{align*}

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$\left(-\dfrac{2}{5}\right) \cdot \left( -\dfrac{1}{3} \right)=$

a
$-\dfrac{2}{15}$
b
$-\dfrac{15}{2}$
c
$-\dfrac{6}{5}$
d
$\dfrac{6}{5}$
e
$\dfrac{2}{15}$

$\left(-\dfrac{1}{2}\right) \cdot \dfrac{5}{3}=$

a
$-\dfrac{3}{10}$
b
$-\dfrac{5}{6}$
c
$\dfrac{5}{6}$
d
$-\dfrac{3}{5}$
e
$\dfrac{3}{10}$

What is (-3.4) \cdot 3.8?

EXPLANATION

We have the product of a negative number and a positive number, which gives a negative number. (-3.4) \cdot 3.8 = -(3.4 \cdot 3.8) = -12.92

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$(-4)\cdot (-5.1)=$

a
$20.4$
b
$-20.4$
c
$20.2$
d
$-22.4$
e
$22.4$

$(-4.2) \cdot (-3.6)=$

a
$15.12$
b
$-15.12$
c
$15.36$
d
$14.82$
e
$-14.82$

Here, we will prove that the product of two negative numbers is positive. Please don't worry if you don't fully understand all the details. Just follow along as best you can. You can circle back later if needed.

To explain why the product of two negatives is positive, we need to state some properties of numbers that we use regularly:

  • Subtracting a number is the same as adding its opposite: a - b = a + (-b) For example, 2-3 = 2 + (-3).

  • The commutative law: For any numbers a and b, we have: a\cdot b = b\cdot a For example, 2\cdot 3 = 3\cdot 2.

  • The distributive law: For any numbers a, b and c, we have: a\cdot (b+c) = a\cdot b + a\cdot c For example, 2\cdot (3+4) = 2\cdot 3 + 2\cdot 4.

Let's now prove the following result:

(-1) \cdot (-1) = 1

We start with the following true equation:

\begin{align*} (-1) \cdot 0 = 0 \end{align*} This is true because any number multiplied by zero equals zero.

Now, since 0=1 -1, we can write the zero on the left-hand side as follows:

(-1) \cdot (1-1) = 0

Subtracting a positive is the same as adding a negative. Therefore:

(-1) \cdot \big(1+ (-1)\big) = 0

We now apply the distributive law:

(-1) \cdot 1+ (-1)\cdot (-1) = 0

Applying the commutative law to the first term on the left-hand side gives:

1\cdot (-1)+ (-1)\cdot (-1) = 0

The number 1\cdot (-1) equals -1, since this just means one copy of -1. Therefore:

-1+ (-1)\cdot (-1) = 0

Finally, adding 1 to both sides of the equation, we finally arrive at:

(-1)\cdot (-1) = 1

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