We can use our knowledge of fraction models to multiply fractions by whole numbers.

For example, let's consider the following product:

\dfrac{3}{10} \times 2.

We start by drawing a fraction model for \dfrac{3}{10}{:}

Multiplying \dfrac{\color{red}3}{10} by \color{blue}2 means that we need to repeat the fraction \color{blue}2 times.

Now, we count the number of shaded pieces.

There are {\color{red}3} \times {\color{blue}2} = 6 shaded pieces in total. Therefore,

\dfrac{3}{10} \times 2 = \dfrac{6}{10}.

FLAG

Consider the diagram above. Write down this multiplication as a repeated addition of fraction models.

EXPLANATION

In the model, we have \dfrac{\color{red}4}{5} multiplied by {\color{blue}3}. This means that we need to make \color{blue}3 copies of the given fraction model.

So, the missing picture is:

FLAG

What picture is missing from the multiplication model above?

a
b
c
d
e

What picture is missing from the multiplication model above?

a
b
c
d
e

Use the model above to calculate \dfrac{5}{6} \times 3.

EXPLANATION

Since we need to multiply \dfrac{\color{red}5}{6} by \color{blue}3 , we repeat the fraction model \color{blue}3 times, as shown below.

There are {\color{red}5} \times {\color{blue}3} = 15 shaded pieces in total. Therefore: \dfrac{5}{6} \times 3 = \dfrac{15}{6}

FLAG

Use the model above to calculate $2 \times \dfrac{2}{5}.$

a
$\dfrac{1}{10}$
b
$\dfrac{2}{10}$
c
$\dfrac{2}{5}$
d
$\dfrac{4}{5}$
e
$\dfrac{1}{5}$

Use the model above to calculate $\dfrac{8}{14} \times 4.$

a
$\dfrac{12}{14}$
b
$\dfrac{24}{14}$
c
$\dfrac{16}{14}$
d
$\dfrac{32}{14}$
e
$\dfrac{28}{14}$

There's another way we can use fraction models to multiply fractions by whole numbers.

To demonstrate, let's consider the following multiplication problem:

\dfrac{2}{9} \times 4

We start by drawing a fraction model to represent \dfrac{2}{9}.

Now, rather than repeating our model 4 times (which would take a long time), we can instead multiply the number of shaded pieces by 4.

Our model has 2 shaded pieces. So, the resulting model must have 2 \times 4 = 8 shaded pieces:

Therefore, we conclude that

\dfrac{2}{9}\times 4 = \dfrac{8}{9}.

FLAG

What number is missing from the multiplication problem above?

EXPLANATION

We have \dfrac{3}{7} on the left and \dfrac{6}{7} on the right.



The shape on the left has 3 shaded pieces, and the shape on the right has 6 shaded pieces. So the number of shaded pieces has increased by a factor of {\color{blue}2}. (That is, the number of shaded pieces has been multiplied by {\color{blue}2}. )

Therefore, the multiplication problem shown is \dfrac{3}{7} \times {\color{blue}2} = \dfrac{6}{7}.

So, the missing number is {\color{blue}2}.

FLAG

What number is missing from the multiplication problem above?

a
$12$
b
$2$
c
$3$
d
$6$
e
$1$

What multiplication problem is represented by the model above?

a
$\dfrac{2}{8} \times 2 = \dfrac{5}{8}$
b
$\dfrac{3}{8} \times 2 = \dfrac{6}{8}$
c
$\dfrac{2}{6} \times 4 = \dfrac{4}{3}$
d
$\dfrac{4}{8} \times 2 = \dfrac{6}{8}$
e
$\dfrac{3}{8} \times 3 = \dfrac{9}{8}$
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