We can use fraction models to multiply unit fractions by whole numbers.

For example, let's consider the following product:

\dfrac 13 \times 2

First, we represent \dfrac{1}{3} using a model:

Multiplication by a whole number is simply a repeated addition. And, since we need to multiply \dfrac{\color{red}1}{3} by {\color{blue}2}, we repeat the fraction model \color{blue}2 times, as shown below.

There are {\color{blue}2} \times {\color{red}1} = 2 shaded pieces in total. Therefore, we conclude that 2 \times \dfrac{1}{3} = \dfrac{2}{3}.

FLAG

Consider the diagram above. Write down this multiplication as a repeated addition of fraction models.

EXPLANATION

In the model, we have \dfrac{\color{red}1}{3} multiplied by {\color{blue}3}. This means that we need to make \color{blue}3 copies of the given fraction model.

So, the missing fraction model is:

FLAG

What picture is missing from the multiplication model above?

a
b
c
d
e

What picture is missing from the multiplication model above?

a
b
c
d
e

Use the model above to calculate 3 \times \dfrac{1}{5}.

EXPLANATION

Since we need to multiply \dfrac{\color{red}1}{5} by \color{blue}3 , we repeat the fraction model \color{blue}3 times, as shown below.

There are {\color{blue}3} \times {\color{red}1} = 3 shaded pieces in total. Therefore, 3 \times \dfrac{1}{5} = \dfrac{3}{5}.

FLAG

Use the model above to calculate $4 \times \dfrac{1}{5}.$

a
$\dfrac{2}{5}$
b
$\dfrac{3}{5}$
c
$\dfrac{4}{5}$
d
$\dfrac{1}{5}$
e
$\dfrac{6}{5}$

Use the model above to calculate $3 \times \dfrac{1}{2}.$

a
$\dfrac16$
b
$\dfrac22$
c
$\dfrac42$
d
$\dfrac45$
e
$\dfrac32$

There's another way we can use fraction models to multiply unit fractions by whole numbers.

To demonstrate, let's consider the multiplication problem below:

\dfrac{1}{10} \times 7

We start by drawing a fraction model to represent \dfrac{1}{10}.

Now, rather than repeating our model 7 times (which would take a long time), we can instead multiply the number of shaded pieces by 7.

Our model has 1 shaded piece. So, the resulting model must have 1 \times 7 = 7 shaded pieces:

Therefore, we conclude that

\dfrac{1}{10}\times 7 = \dfrac{7}{10}.

FLAG

What multiplication problem is represented by the model above?

EXPLANATION

We have \dfrac{1}{9} on the left and \dfrac{4}{9} on the right.

Therefore, we have \dfrac{1}{9} \times 4 = \dfrac{4}{9}.

Note: We can swap the factors on the left-hand side. So, the following would be a correct answer too: 4 \times \dfrac{1}{9} = \dfrac{4}{9}

FLAG

What multiplication problem is represented by the model above?

a
$\dfrac{4}{5} \times 4 = \dfrac{1}{5}$
b
$\dfrac{4}{6} \times 4 = \dfrac{1}{6}$
c
$\dfrac{5}{6} \times 4 = \dfrac{2}{6}$
d
$\dfrac{1}{6} \times 4 = \dfrac{4}{6}$
e
$\dfrac{1}{5} \times 4 = \dfrac{4}{5}$

What multiplication problem is represented by the model above?

a
$\dfrac{1}{3} \times 3 = \dfrac{2}{4}$
b
$\dfrac{3}{4} \times 3 = \dfrac{1}{4}$
c
$\dfrac{1}{4} \times 3 = \dfrac{3}{4}$
d
$\dfrac{1}{4} \times 3 = \dfrac{2}{4}$
e
$\dfrac{1}{3} \times 3 = \dfrac{3}{4}$

What number is missing from the multiplication problem above?

EXPLANATION

We have \dfrac{1}{5} on the left and \dfrac{3}{5} on the right.

The shape on the left has 1 shaded piece, and the shape on the right has 3 shaded pieces. So the number of shaded pieces has increased by a factor of {\color{blue}3}.

Therefore, we have \dfrac{1}{5} \times {\color{blue}3} = \dfrac{3}{5}.

So, the missing number is {\color{blue}3}.

FLAG

What number is missing from the multiplication problem above?

a
$3$
b
$4$
c
$6$
d
$2$
e
$5$

What number is missing from the multiplication problem above?

a
$3$
b
$5$
c
$1$
d
$2$
e
$4$
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