When we want to multiply two binomials, we take each term of the first binomial and multiply it by the second binomial. Then, we simplify by collecting like terms.

For example, to multiply ({\color{blue}{x}} + {\color{red}{3}}) and (x + 2), we multiply {\color{blue}{x}} and (x + 2), and then we add this to the product of {\color{red}{3}} and (x+2) :

\eqalign{ ({\color{blue}{x}} + {\color{red}{3}})(x + 2) &= \\[5pt] {\color{blue}{x}}(x + 2) + {\color{red}{3}}(x + 2) &= \\[5pt] x^2 + 2x + 3x + 6 &= \\[5pt] x^2 + 5x + 6 }

FLAG

Expand and simplify (y + 5)(y - 2).

EXPLANATION

We take each term of the first binomial and multiply it by the second binomial. Then, we simplify by collecting like terms.

\eqalign{ (y + 5)(y - 2) &= \\ y(y-2) + 5(y-2) &=\\ y^2-2y +5y-10 &=\\ y^2 + 3y - 10 }

FLAG

$(q + 6)(q + 2) =$

a
$q+8$
b
$9q+12$
c
$q^2 +8q + 12$
d
$q^2+12$
e
$9q^2+12$

Expand the following product of binomials. Write your answer in standard form.

a
b
c
d
e

Expand and simplify (2n - 1)(3n - 6).

EXPLANATION

We take each term of the first binomial and multiply it by the second binomial. Then, we simplify by collecting like terms.

\eqalign{ (2n - 1)(3n - 6) &= \\ 2n(3n - 6) + (-1)(3n - 6) &= \\ 6n^2 - 12n - 3n + 6 &= \\ 6n^2 - 15n + 6 }

FLAG

Expand the following product of binomials. Write your answer in standard form.

a
b
c
d
e

$(3x + 2)(5x - 4)=$

a
$15x^2 -2x - 8$
b
$15x^2-8$
c
$15x^2+2x+8$
d
$15x^2 +22x - 8$
e
$15x^2+2x-8$

Expand (p^2-q^2)(2p+3q).

EXPLANATION

We take each term of the first binomial and multiply it by the second binomial. Then, we simplify by collecting like terms.

\begin{align*} (p^2-q^2)(2p+3q) &=\\ p^2(2p+3q) + (-q^2)(2p+3q) &=\\ 2p^3 +3p^2q - 2pq^2 -3q^3 & \end{align*}

We cannot simplify the above expression any further because there are no like terms.

FLAG

$(5a+b)(a+3b)=$

a
$a^2+14ab+3b^2$
b
$5a^2+16ab+3b^2$
c
$5a^2+12ab+b^2$
d
$5a^2+14ab+3b^2$
e
$a^2+16ab+b^2$

$(7u^2-6v)(v-u) =$

a
b
c
d
e
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