Notice that $354$ in expanded form is \[ 354 = 300+50+4. \] So, we can compute $6\times 354$ by filling in the missing numbers and adding the results.

First, let's find the missing values:

\begin{align*} 6 \times 300 &= \fbox{$\,1,800\,$} \\[5pt] 6 \times 50 &= \fbox{$\,300\,$} \\[5pt] 6 \times 4 &= \fbox{$\,24\,$} \end{align*}

Let's now add these results:

\[ \begin{array}{cccccccc} & \!\!\!\! {\small\color{blue}1} \!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! \!\!\!\! & \\ & \!\!\!\! 1 \!\!\!\! & \!\!\!\! 8 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 4 \!\!\!\! \\ \hline & \!\!\!\! 2 \!\!\!\! & \!\!\!\! 1 \!\!\!\!& \!\!\!\! 2 \!\!\!\!& \!\!\!\! 4 \!\!\!\! \end{array} \]

Therefore,

\[ 6\times354 = 2,124. \]

Notice that $875$ in expanded form is \[ 875 = 800+70+5. \] So, we can compute $875\times9$ by filling in the missing numbers and adding the results.

First, let's find the missing values:

\begin{align*} 800 \times 9 &= \fbox{$\,7,200\,$} \\[5pt] 70 \times 9 &= \fbox{$\,630\,$} \\[5pt] 5 \times 9 &= \fbox{$\,45\,$} \end{align*}

Let's now add these results:

\[ \begin{array}{cccccccc} & \!\!\!\! 7 \!\!\!\! & \!\!\!\! 2 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 6 \!\!\!\! & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 4 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & \!\!\!\! 7 \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! 7 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \end{array} \]

Therefore,

\[ 875\times9 = 7,875. \]

First, let's write the three-digit number $(217)$ in expanded form:

\[ 217 = {\color{blue}{200}} + {\color{blue}{10}} + {\color{blue}{7}} . \]

We now multiply all numbers in our expanded form by ${\color{red}{4}}\mathbin{:}$

\begin{align*} {\color{red}{4}} \times {\color{blue}{200}} &= 800 \\[5pt] {\color{red}{4}} \times {\color{blue}{10}} &= 40 \\[5pt] {\color{red}{4}} \times {\color{blue}{7}} &= 28 \end{align*}

Let's now add these results:

\[ \begin{array}{cccccccc} & \!\!\!\! \!\!\!\! & \!\!\!\! 8 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 4 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \hline & \!\!\!\! \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! 6 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \end{array} \]

Therefore,

\[ 4 \times 217 = 868. \]

First, let's write the three-digit number $(628)$ in expanded form:

\[ 628 = {\color{blue}{600}} + {\color{blue}{20}} + {\color{blue}{8}}. \]

We now multiply all numbers in our expanded form by ${\color{red}{7}}\mathbin{:}$

\begin{align*} {\color{blue}{600}} \times {\color{red}{7}} &= 4,200 \\[5pt] {\color{blue}{20}} \times {\color{red}{7}} &= 140 \\[5pt] {\color{blue}{8}} \times {\color{red}{7}} &= 56 \end{align*}

Let's now add these results:

\[ \begin{array}{cccccccc} & \!\!\!\! 4 \!\!\!\! & \!\!\!\! 2 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 1 \!\!\!\! & \!\!\!\! 4 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 6 \!\!\!\! \\ \hline & \!\!\!\! 4 \!\!\!\! & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 9 \!\!\!\!& \!\!\!\! 6 \!\!\!\! \end{array} \]

Therefore,

\[ 628 \times 7 = 4,396. \]

To figure out the total number of jelly beans, we need to compute the value of

\[ {\color{red}{3}} \times 239. \]

First, let's write the three-digit number $(239)$ in expanded form:

\[ 239 = {\color{blue}{200}} + {\color{blue}{30}} + {\color{blue}{9}}. \]

We now multiply all numbers in our expanded form by ${\color{red}{3}}\mathbin{:}$

\begin{align*} {\color{red}{3}} \times {\color{blue}{200}} &= 600 \\[5pt] {\color{red}{3}} \times {\color{blue}{30}} &= 90 \\[5pt] {\color{red}{3}} \times {\color{blue}{9}} &= 27 \end{align*}

Let's now add these results:

\[ \begin{array}{cccccccc} & & \!\!\!\! {\small\color{blue}1} \!\!\!\! & \!\!\!\! \!\!\!\! & \\ & \!\!\!\! \!\!\!\! & \!\!\!\! 6 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 9 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \hline & \!\!\!\! \!\!\!\! & \!\!\!\! 7 \!\!\!\!& \!\!\!\! 1 \!\!\!\!& \!\!\!\! 7 \!\!\!\! \end{array} \]

Therefore, Ross has $717$ jelly beans.

To figure out the total amount of grain that was transported, we need to compute the value of

\[ {\color{red}{9}} \times 987. \]

First, let's write the three-digit number $(987)$ in expanded form:

\[ 987 = {\color{blue}{900}} + {\color{blue}{80}} + {\color{blue}{7}}. \]

We now multiply all numbers in our expanded form by ${\color{red}{9}}\mathbin{:}$

\begin{align*} {\color{red}{9}} \times {\color{blue}{900}} &= 8\,100 \\[5pt] {\color{red}{9}} \times {\color{blue}{80}} &= 720 \\[5pt] {\color{red}{9}} \times {\color{blue}{7}} &= 63 \end{align*}

Let's now add these results:

\[ \begin{array}{cccccccc} & \!\!\!\! 8 \!\!\!\! & \!\!\!\! 1 \!\!\!\! & \!\!\!\! 0 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 7 \!\!\!\! & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 0 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! \!\!\!\! & \!\!\!\! 6 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \\ \hline & \!\!\!\! 8 \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! 8 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \end{array} \]

Therefore, $8,883$ tons of grain were transported.