Let's consider the following fraction:

\dfrac12

We can generate equivalent fractions by multiplying the numerator and denominator by any whole number.

For example, multiplying the numerator and denominator by {\color{red}{2}}, we get

\dfrac12 = \dfrac{1\times {\color{red}{2}}}{2\times {\color{red}{2}}} = \dfrac{2}{4}.

Similarly, by multiplying the numerator and denominator by {\color{blue}{3}}, we get

\dfrac12 = \dfrac{1\times {\color{blue}{3}}}{2\times {\color{blue}{3}}} = \dfrac{3}{6}.

Therefore, the following fractions are all equivalent:

\dfrac12, \qquad\dfrac24, \qquad \dfrac36

We can check that these fractions are equivalent using fraction models:

All three models have the same shape and the same shaded area. Therefore, they represent equivalent fractions.

FLAG

Create a fraction equivalent to \dfrac{4}{3} with a denominator of 9.

EXPLANATION

To make an equivalent fraction with a denominator of 9, we multiply the numerator and the denominator of \dfrac{4}{3} by 3.

\dfrac{4}{3} = \dfrac{4 \times 3}{3 \times 3}=\dfrac{12}{9}

Therefore, \dfrac{4}{3}=\dfrac{12}{9}.

FLAG

$\dfrac{1}{4} = $

a
$\dfrac{5}{12}$
b
$\dfrac{6}{12}$
c
$\dfrac{3}{12}$
d
$\dfrac{7}{12}$
e
$\dfrac{8}{12}$

Create a fraction equivalent to $\dfrac{1}{2}$ that has a denominator of $10.$

a
b
c
d
e

Create a fraction equivalent to $\dfrac{2}{3}$ that has a denominator of $6.$

a
b
c
d
e

We can also divide the numerator and denominator of a fraction by the same number to give an equivalent fraction.

For example, let's consider the following fraction:

\dfrac{6}{12}

Let's create some equivalent fractions by dividing:

  • Notice that 6 and 12 both have {\color{blue}{2}} as a factor. Therefore, we can divide our fraction by {\color{blue}{2}} to create an equivalent fraction:

\dfrac{6}{12} = \dfrac{6\div {\color{blue}{2}} }{12 \div {\color{blue}{2}}} = \dfrac36

  • Similarly, 6 and 12 both have {\color{red}{3}} as a factor. Therefore, we can divide our fraction by {\color{red}{3}} to create an equivalent fraction:

\dfrac{6}{12} = \dfrac{6\div {\color{red}{3}} }{12 \div {\color{red}{3}}} = \dfrac24

  • Finally, 6 and 12 also have {\color{purple}{6}} as a factor. Therefore, we can divide our fraction by {\color{purple}{6}} to create an equivalent fraction:

\dfrac{6}{12} = \dfrac{6\div {\color{purple}{6}} }{12 \div {\color{purple}{6}}} = \dfrac12

Therefore, the following fractions are all equivalent:

\dfrac{6}{12}, \qquad \dfrac{3}{6}, \qquad \dfrac{2}{4}, \qquad \dfrac12

FLAG

Create a fraction equivalent to \dfrac{12}{8} with a denominator of 2.

EXPLANATION

To make a denominator of 2 , we divide the numerator and the denominator of \dfrac{12}{8} by 4.

\dfrac{12}{8} = \dfrac{12 \div 4}{8 \div 4} =\dfrac{3}{2}

Therefore, \dfrac{12}{8} = \dfrac{3}{2}.

FLAG

Create a fraction equivalent to $\dfrac{8}{20}$ that has a denominator of $5.$

a
b
c
d
e

$\dfrac{21}{18} =$

a
$\dfrac{5}{6}$
b
$\dfrac{7}{6}$
c
$\dfrac{4}{6}$
d
$\dfrac{9}{6}$
e
$\dfrac{8}{6}$

To express a whole number as a fraction, we use the number itself as the numerator and put it over a denominator of 1.

For example, the number 3 can be written as a fraction in the following way:

3 = \dfrac{3}{1}

We can now find some equivalent fractions. For example:

  • multiplying our fraction by {\color{blue}{2}}, we get \dfrac{3}{1} = \dfrac{3\times {\color{blue}{2}} }{1\times {\color{blue}{2}}} = \dfrac62.

  • multiplying our fraction by {\color{red}{3}}, we get \dfrac{3}{1} = \dfrac{3\times {\color{red}{3}} }{1\times {\color{red}{3}}} = \dfrac93.

Therefore, the following numbers are all equivalent:

3, \qquad \dfrac31, \qquad \dfrac62, \qquad \dfrac93

FLAG

What is the missing digit in the following equality?

5=\dfrac{\,\fbox{[math]\phantom{0}[/math]}}{4}

EXPLANATION

Let's write 5 as a fraction with denominator 1 :

5 = \dfrac{5}{1}

To make a denominator of 4, we multiply the numerator and the denominator of \dfrac{5}{1} by 4.

\dfrac{5}{1} = \dfrac{5 \times 4}{1 \times 4} = \dfrac{\color{blue}20}{4}

Therefore, the missing number is {\color{blue}{20}}.

FLAG

What is the missing digit in the following equality? \[ 7 = \dfrac{21}{\,\fbox{$\phantom{0}$}} \]

a
$6$
b
$4$
c
$9$
d
$12$
e
$3$

$6 = $

a
$\dfrac{20}{4}$
b
$\dfrac{22}{4}$
c
$\dfrac{24}{4}$
d
$\dfrac{18}{4}$
e
$\dfrac{28}{4}$

Create a fraction equivalent to the number $7$ that has a denominator of $4.$

a
b
c
d
e
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