To add two mixed numbers where the fractional parts have unlike denominators, we apply the following steps:
Step 1: First, we add whole numbers to whole numbers.
Step 2: Then, we add fractions to fractions, converting them to equivalent fractions with a common denominator where necessary.
Step 3: Combine the results from steps 1 and 2 to form a mixed number.
So, let's find the value of
Step 1: Adding the whole numbers, we get
Step 2: We now add the fractions:
Here, we can make a common denominator of To put over a denominator of we multiply the numerator and denominator by :
We can now add the fractions. We keep the denominator the same, and we add the numerators.
Step 3: We now combine the results to get our final answer:
What is the value of
To add two mixed numbers, we add whole numbers to whole numbers and fractions to fractions.
Step 1: Adding the whole numbers, we get
Step 2: Now we add the fractions:
To add two fractions with unlike denominators, we must express each fraction as an equivalent fraction with a common denominator.
Here, we can make a common denominator of
To put over a denominator of we multiply the numerator and denominator by
We can now add the fractions. We keep the denominator the same, and we add the numerators.
Notice that we can simplify the above fraction by dividing the numerator and denominator by
Step 3: Combining our results gives:
$2\,\dfrac{3}{8} + 2\,\dfrac 1 4 = $
a
|
$3\,\dfrac 1 4$ |
b
|
$3\,\dfrac 3 8$ |
c
|
$4\,\dfrac 3 4$ |
d
|
$4\,\dfrac 5 8$ |
e
|
$4\,\dfrac 3 8$ |
$1\,\dfrac{3}{10} + 2\,\dfrac 1 5 = $
a
|
$3\,\dfrac 3 5$ |
b
|
$4\,\dfrac 2 5$ |
c
|
$4\,\dfrac 1 2$ |
d
|
$3\,\dfrac 1 2$ |
e
|
$3\,\dfrac 2 5$ |
Calculate the value of
To add two mixed numbers, we add whole numbers to whole numbers and fractions to fractions.
Step 1: Adding the whole numbers, we get
Step 2: Now we add the fractions:
To add the fractions, we need to find the least common multiple of the denominators ( and ).
Multiples of
Multiples of
Therefore, the least common denominator of and is
To put over a denominator of we multiply the numerator and denominator by
To put over a denominator of we multiply the numerator and denominator by
We can now add the fractions. We keep the denominator the same, and we add the numerators:
Step 3: We combine the results to get our final answer:
What is the missing number in the following equality?
\[2\,\dfrac{1}{7} + 4\,\dfrac 2 3 = 6\,\dfrac{\,\fbox{$\phantom{0}$}}{21} \]
a
|
$16$ |
b
|
$4$ |
c
|
$17$ |
d
|
$5$ |
e
|
$10$ |
$ 2\,\dfrac{1}{8} + 4\,\dfrac 5 6 = $
a
|
$6\,\dfrac {23}{24}$ |
b
|
$6\,\dfrac {19}{24}$ |
c
|
$6\,\dfrac {7}{8}$ |
d
|
$7\,\dfrac {1}{24}$ |
e
|
$6\,\dfrac {11}{12}$ |
Sometimes, when we add two mixed numbers, the sum of the fractional parts is an improper fraction. In those cases, we must convert the improper fraction to a mixed number. Then, we can add the whole numbers and fractions as usual.
To illustrate, let's compute
Step 1: Adding the whole numbers, we get
Step 2: Now, we add the fractions:
Notice that this is an improper fraction. We can convert the fraction to a mixed number in the usual way:
Step 3: We combine the results to get our final answer:
Notice that we needed to add the whole numbers one final time.
Find the value of
To add two mixed numbers, we add whole numbers to whole numbers and fractions to fractions.
Step 1: Adding the whole numbers, we get
Step 2: Now we add the fractions:
To add two fractions with unlike denominators, we must express each fraction as an equivalent fraction with a common denominator.
In this question, we can make a common denominator of
To put over a denominator of we multiply the numerator and denominator by :
We can now add the fractions. We keep the denominator the same, and we add the numerators.
Notice that this is an improper fraction. We can convert the fraction to a mixed number in the usual way:
Step 3: We combine the results to get our answer.
Notice that we needed to add the whole numbers one final time.
What is the missing number in the following equality?
\[5\,\dfrac{3}{4} + 1\,\dfrac 5 6 = 7\,\dfrac{\,\fbox{$\phantom{0}$}}{12} \]
a
|
$5$ |
b
|
$1$ |
c
|
$11$ |
d
|
$7$ |
e
|
$2$ |
$3\,\dfrac{1}{2} + 4\,\dfrac 7 8 = $
a
|
$ 8\,\dfrac 3{8}$ |
b
|
$ 7\,\dfrac 5{8}$ |
c
|
$ 8\,\dfrac 1{8}$ |
d
|
$ 9\,\dfrac 3{8}$ |
e
|
$7\,\dfrac 1{8}$ |