First, we line up our numbers (ones over ones, tens over tens, and hundreds over hundreds):

\[ \begin{array}{cccccccc} & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 8 \!\!\!\! & \!\!\!\! 9 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 4 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. Subtracting the ones, ${\color{blue}9} - {\color{blue}4} = {\color{blue}5}{:}$

\[ \begin{array}{cccccccc} & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! {\color{blue}9} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! {\color{blue}4} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}5} \!\!\!\! \end{array} \]

Step 2. Subtracting the tens, ${\color{blue}8} - {\color{blue}5} = {\color{blue}3}{:}$

\[ \begin{array}{cccccccc} & \!\!\!\! 3 \!\!\!\! & \!\!\!\! {\color{blue}8} \!\!\!\!& \!\!\!\! 9 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! {\color{blue}5} \!\!\!\!& \!\!\!\! 4 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}3} \!\!\!\!& \!\!\!\! 5 \!\!\!\! \end{array} \]

Step 3. Subtracting the hundreds, ${\color{blue}3} - {\color{blue}0} = {\color{blue}3}{:}$

\[ \begin{array}{cccccccc} & \!\!\!\! {\color{blue}3} \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! 9 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! {\color{blue}0} \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 4 \!\!\!\! \\ \hline & \!\!\!\! {\color{blue}3} \!\!\!\! & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 5 \!\!\!\! \end{array} \]

Therefore, $389 - 54 = 335.$

To find out how many grams of chocolate chips Jill has left, we need to calculate $187-62.$

First, we line up our numbers (ones over ones, tens over tens, and hundreds over hundreds):

\[ \begin{array}{cccccccc} & \!\!\!\! 1 \!\!\!\! & \!\!\!\! 8 \!\!\!\! & \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 6 \!\!\!\!& \!\!\!\! 2 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. Subtracting the ones, ${\color{blue}7} - {\color{blue}2} = {\color{blue}5}{:}$

\[ \begin{array}{cccccccc} & \!\!\!\! 1 \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! {\color{blue}7} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 6 \!\!\!\!& \!\!\!\! {\color{blue}2} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}5} \!\!\!\! \end{array} \]

Step 2. Subtracting the tens, ${\color{blue}8} - {\color{blue}6} = {\color{blue}2}{:}$

\[ \begin{array}{cccccccc} & \!\!\!\! 1 \!\!\!\! & \!\!\!\! {\color{blue}8} \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! {\color{blue}6} \!\!\!\!& \!\!\!\! 2 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}2} \!\!\!\!& \!\!\!\! 5 \!\!\!\! \end{array} \]

Step 3. Subtracting the hundreds, ${\color{blue}1} - {\color{blue}0} = {\color{blue}1}{:}$

\[ \begin{array}{cccccccc} & \!\!\!\! {\color{blue}1} \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! {\color{blue}0} \!\!\!\! & \!\!\!\! 6 \!\!\!\!& \!\!\!\! 2 \!\!\!\! \\ \hline & \!\!\!\! {\color{blue}1} \!\!\!\! & \!\!\!\! 2 \!\!\!\! & \!\!\!\! 5 \!\!\!\! \end{array} \]

Therefore, Jill has $125$ grams of chocolate chips left.

First, we line up our numbers:

\[ \begin{array}{cccccccc} & \!\!\!\! 5 \!\!\!\! & \!\!\!\! 5 \!\!\!\! & \!\!\!\! 4 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. We cannot compute $4 - 8.$ So, we borrow $1$ from the tens place:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{\color{red}4} \!\!\! & \!\!\! \small{\color{red}14} \!\!\!\! \\ &\!\!\!\! 5 \!\!\! & \!\!\! \cancel{5} \!\!\!& \!\!\! \cancel{4} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 2 \!\!\!& \!\!\! 8 \!\!\!\! \\ \hline & \!\!\!\! \!\!\! & \!\!\! \!\!\! & \!\!\! 6 \!\!\!\! \end{array} \]

Step 2. Then, we subtract ones from ones, tens from tens, and hundreds from hundreds:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{4} \!\!\! & \!\!\! \small{14} \!\!\!\! \\ &\!\!\!\! 5 \!\!\! & \!\!\! \cancel{5} \!\!\!& \!\!\! \cancel{4} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! 0 \!\!\! & \!\!\! 2 \!\!\!& \!\!\! 8 \!\!\!\! \\ \hline & \!\!\!\! 5 \!\!\! & \!\!\! 2 \!\!\! & \!\!\! 6 \!\!\!\! \end{array} \]

Therefore, $554 - 28 = 526.$

First, we line up our numbers:

\[ \begin{array}{cccccccc} & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 7 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. Subtracting the ones, ${\color{blue}7} - {\color{blue}5} = {\color{blue}2}{:}$

\[ \begin{array}{cccccccc} &\!\!\!\! 3 \!\!\!\! & \!\!\!\! 3 \!\!\!\!& \!\!\!\! {\color{blue}7} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 7 \!\!\!\!& \!\!\!\! {\color{blue}5} \!\!\!\! \\ \hline &\!\!\!\! \!\!\!\! & \!\!\!\! \!\!\!& \!\!\!\! {\color{blue}2} \!\!\!\! \end{array} \]

Step 2. We cannot compute $3 - 7.$ So, we borrow $1$ from the hundreds place:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \small{\color{red}2} \!\!\! & \!\!\! \small{\color{red}13} \!\!\! & \!\!\! \!\!\!\! \\ &\!\!\!\! \cancel{3} \!\!\! & \!\!\! \cancel{3} \!\!\!& \!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 7 \!\!\!& \!\!\! 5 \!\!\!\! \\ \hline & \!\!\!\! \!\!\! & \!\!\! \!\!\! & \!\!\! 2 \!\!\!\! \end{array} \]

Step 3: Then, we subtract tens and hundreds:

\[ \begin{array}{cccccccc} &\!\!\!\! \small{2} \!\!\! & \!\!\! \small{13} \!\!\! & \!\!\! \!\!\!\! \\ &\!\!\!\! \cancel{3} \!\!\! & \!\!\! \cancel{3} \!\!\!& \!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! {0} \!\!\! & \!\!\! {7} \!\!\!& \!\!\! 5 \!\!\!\! \\ \hline & \!\!\!\! {2} \!\!\! & \!\!\! {6} \!\!\! & \!\!\! 2 \!\!\!\! \end{array} \]

Therefore, $337 - 75 = 262.$

First, we line up our numbers:

\[ \begin{array}{cccccccc} & \!\!\!\! 5 \!\!\!\! & \!\!\!\! 4 \!\!\!\! & \!\!\!\! 1 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 4 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. We cannot compute $1 - 3.$ So, we borrow $1$ from the tens place. Then, subtracting the ones, ${\color{blue}11} - {\color{blue}3} = {\color{blue}8}{:}$

\[ \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{3} \!\!\! & \!\!\! \small{\color{blue}11} \!\!\!\! \\ &\!\!\!\! 5 \!\!\! & \!\!\! \cancel{4} \!\!\!& \!\!\! \cancel{1} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 4 \!\!\!& \!\!\! {\color{blue}3} \!\!\!\! \\ \hline &\!\!\!\! \!\!\! & \!\!\! \!\!\!& \!\!\! {\color{blue}8} \!\!\!\! \end{array} \]

Step 2. We cannot compute $3 - 4.$ So, we borrow $1$ from the hundreds place. Then, we subtract tens and hundreds:

\[ \begin{array}{cccccccc} &\!\!\!\! \small4 \!\!\! & \!\!\! \small{13} \!\!\! & \!\!\! \small {11}\!\!\!\! \\ &\!\!\!\! \cancel{5} \!\!\! & \!\!\! \cancel{4} \!\!\!& \!\!\! \cancel{1} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! 0 \!\!\! & \!\!\! 4 \!\!\!& \!\!\! 3 \!\!\!\! \\ \hline &\!\!\!\! 4 \!\!\! & \!\!\! 9 \!\!\!& \!\!\! 8 \!\!\!\! \end{array} \]

Therefore, $541 - 43 = 498.$

To find out the length of the other piece of rope, we need to calculate $342-87.$

First, we line up our numbers:

\[ \begin{array}{cccccccc} & \!\!\!\! 3 \!\!\!\! & \!\!\!\! 4 \!\!\!\! & \!\!\!\! 2 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 8 \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. We cannot compute $2 - 7.$ So, we borrow $1$ from the tens place. Then, subtracting the ones, ${\color{blue}12} - {\color{blue}7} = {\color{blue}5}{:}$

\[ \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{3} \!\!\! & \!\!\! \small{\color{blue}12} \!\!\!\! \\ &\!\!\!\! 3 \!\!\! & \!\!\! \cancel{4} \!\!\!& \!\!\! \cancel{2} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 8 \!\!\!& \!\!\! {\color{blue}7} \!\!\!\! \\ \hline &\!\!\!\! \!\!\! & \!\!\! \!\!\!& \!\!\! {\color{blue}5} \!\!\!\! \end{array} \]

Step 2. We cannot compute $3 - 8.$ So, we borrow $1$ from the hundreds place. Then, we subtract tens and hundreds:

\[ \begin{array}{cccccccc} &\!\!\!\! \small{2} \!\!\! & \!\!\! \small{13} \!\!\! & \!\!\! \small{12} \!\!\!\! \\ &\!\!\!\! \cancel{3} \!\!\! & \!\!\! \cancel{4} \!\!\!& \!\!\! \cancel{2} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! 0 \!\!\! & \!\!\! 8 \!\!\!& \!\!\! 7 \!\!\!\! \\ \hline & \!\!\!\! 2 \!\!\! & \!\!\! 5 \!\!\! & \!\!\! 5 \!\!\!\! \end{array} \]

Therefore, the second piece of rope is $255\,\textrm{cm}$ long.

First, we line up our numbers:

\[ \begin{array}{cccccccc} & \!\!\!\! 2 \!\!\!\! & \!\!\!\! 0 \!\!\!\! & \!\!\!\! 5 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 1 \!\!\!\!& \!\!\!\! 9 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. We cannot compute $5 - 9,$ and there are $0$ tens to borrow from. So, we borrow $1$ from the hundreds place first:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \small{\color{red}1} \!\!\! & \!\!\! \small{\color{red}10} \!\!\! & \!\!\! \!\!\!\! \\ &\!\!\!\! \cancel{2} \!\!\! & \!\!\! \cancel{0} \!\!\!& \!\!\! 5 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 1 \!\!\!& \!\!\! 9 \!\!\!\! \\ \hline & \!\!\!\! \!\!\! & \!\!\! \!\!\! & \!\!\! \!\!\!\! \end{array} \]

Then, we borrow $1$ from the tens place:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{\color{red}9} \!\!\! & \!\!\! \small{\color{red}15} \!\!\!\! \\ &\!\!\!\! \small1 \!\!\! & \!\!\! \small\cancel{10} \!\!\! & \!\!\! \small\cancel{5} \!\!\!\! \\ &\!\!\!\! \cancel{2} \!\!\! & \!\!\! \cancel{0} \!\!\!& \!\!\! \cancel{5} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 1 \!\!\!& \!\!\! 9 \!\!\!\! \\ \hline & \!\!\!\! \!\!\! & \!\!\! \!\!\! & \!\!\! \!\!\!\! \end{array} \]

Step 2. Then, we subtract ones, tens, and hundreds:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small 9 \!\!\! & \!\!\! \small{15} \!\!\!\! \\ &\!\!\!\! \small1 \!\!\! & \!\!\! \small\cancel{10} \!\!\! & \!\!\!\small{ \cancel5} \!\!\!\! \\ &\!\!\!\! \cancel{2} \!\!\! & \!\!\! \cancel{0} \!\!\!& \!\!\! \cancel{5} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! 0 \!\!\! & \!\!\! 1 \!\!\!& \!\!\! 9 \!\!\!\! \\ \hline & \!\!\!\! 1 \!\!\! & \!\!\! 8 \!\!\! & \!\!\! 6 \!\!\!\! \end{array} \]

Therefore, $205 - 19 = 186.$

To find out how many bags of feed will be left in the warehouse, we need to calculate $207-78.$

First, we line up our numbers:

\[ \begin{array}{cccccccc} & \!\!\!\! 2 \!\!\!\! & \!\!\!\! 0 \!\!\!\! & \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\!\! & \!\!\!\! 7 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \hline & & & & \end{array} \]

Next, we proceed by subtracting the numbers in each place value (from right to left):

Step 1. We cannot compute $7 - 8,$ and there are $0$ tens to borrow from. So, we borrow $1$ from the hundreds place first:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \small{\color{red}1} \!\!\! & \!\!\! \small{\color{red}10} \!\!\! & \!\!\! \!\!\!\! \\ &\!\!\!\! \cancel{2} \!\!\! & \!\!\! \cancel{0} \!\!\!& \!\!\! 7 \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 7 \!\!\!& \!\!\! 8 \!\!\!\! \\ \hline & \!\!\!\! \!\!\! & \!\!\! \!\!\! & \!\!\! \!\!\!\! \end{array} \]

Then, we borrow $1$ from the tens place:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{\color{red}9} \!\!\! & \!\!\! \small{\color{red}17} \!\!\!\! \\ &\!\!\!\! \small{1} \!\!\! & \!\!\! \cancel{\small{10}} \!\!\! & \!\!\! \cancel{\small{7}} \!\!\!\! \\ &\!\!\!\! \cancel{2} \!\!\! & \!\!\! \cancel{0} \!\!\!& \!\!\! \cancel{7} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! \!\!\! & \!\!\! 7 \!\!\!& \!\!\! 8 \!\!\!\! \\ \hline & \!\!\!\! \!\!\! & \!\!\! \!\!\! & \!\!\! \!\!\!\! \end{array} \]

Step 2. Then we subtract ones, tens, and hundreds:

\[ \require{cancel} \begin{array}{cccccccc} &\!\!\!\! \!\!\! & \!\!\! \small{9} \!\!\! & \!\!\! \small{17} \!\!\!\! \\ &\!\!\!\! \small{1} \!\!\! & \!\!\! \cancel{\small{10}} \!\!\! & \!\!\! \cancel{\small{7}} \!\!\!\! \\ &\!\!\!\! \cancel{2} \!\!\! & \!\!\! \cancel{0} \!\!\!& \!\!\! \cancel{7} \!\!\!\! \\ \!\!\!\!-\!\!\!\! & \!\!\!\! 0 \!\!\! & \!\!\! 7 \!\!\!& \!\!\! 8 \!\!\!\! \\ \hline & \!\!\!\! 1 \!\!\! & \!\!\! 2 \!\!\! & \!\!\! 9 \!\!\!\! \end{array} \]

Therefore, there will be $129$ bags of feed remaining in the warehouse.