How can we subtract fractions, like \dfrac{2}{4} - \dfrac{5}{4}?

Since both fractions have the same denominator ( 4 ), we can combine them into one fraction.

\begin{align*} \dfrac{2}{4} - \dfrac{5}{4} &=\dfrac{2 - 5}{4} \end{align*}

Now, we work out 2-5 using our number line:

We get 2-5=-3, and therefore

\begin{align*} \dfrac{2-5}{4} = \dfrac{-3}{4} = -\dfrac{3}{4}. \end{align*}

Note: If two fractions have different denominators, we need to put them over a common denominator first and then subtract!

FLAG

Find the value of \dfrac{5}{12} - \dfrac{11}{12}.

EXPLANATION

Since both fractions have the same denominators, we can combine them into one fraction, which gives \dfrac{5}{12} - \dfrac{11}{12} = \dfrac{5 - 11}{12}.

Now, we work out 5 - 11 using a number line:

So, we get \dfrac{5 - 11}{12} = \dfrac{-6}{12} = -\dfrac{6}{12}.

Finally, we simplify: -\dfrac{6}{12} = -\dfrac{6 \div 6}{12 \div 6} = -\dfrac{1}{2}

Therefore, we conclude that \dfrac{5}{12} - \dfrac{11}{12} = -\dfrac{1}{2}.

FLAG

Find the value of $\dfrac{2}{11}-\dfrac{5}{11}.$

a
$-\dfrac{7}{11}$
b
$-\dfrac{3}{11}$
c
$\dfrac{3}{11}$
d
$-\dfrac{4}{11}$
e
$\dfrac{7}{11}$

Find the value of $-\dfrac{2}{3}-\dfrac{8}{3}.$

a
$-\dfrac{4}{3}$
b
$-\dfrac{10}{3}$
c
$-\dfrac{5}{3}$
d
$-3$
e
$-2$

Calculate the value of \dfrac{1}{3} - \dfrac{5}{6}.

EXPLANATION

We write \dfrac{1}{3} as \dfrac{2}{6} and then we simply subtract the numerators. This gives \dfrac{2}{6} - \dfrac{5}{6} = \dfrac{2 - 5}{6}.

Now, we work out 2 - 5 using a number line:

So we get \dfrac{2 - 5}{6} = \dfrac{-3}{6} = -\dfrac{3}{6}.

Finally, we simplify: -\dfrac{3}{6} = -\dfrac{3 \div 3}{6 \div 3} =-\dfrac{1}{2}

Therefore, we conclude that \dfrac{1}{3} - \dfrac{5}{6} = -\dfrac{1}{2}.

FLAG

$1-\dfrac{4}{3}=$

a
$\dfrac{2}{3}$
b
$-1$
c
$1$
d
$-\dfrac{5}{3}$
e
$-\dfrac{1}{3}$

Calculate the value of $-\dfrac{1}{4}-\dfrac{5}{8}.$

a
$\dfrac{3}{8}$
b
$-\dfrac{7}{8}$
c
$-\dfrac{5}{8}$
d
$\dfrac{3}{4}$
e
$-\dfrac{3}{4}$

Calculate the value of \dfrac{1}{4} - \dfrac{5}{6}.

EXPLANATION

We write \dfrac{1}{4} as \dfrac{3}{12} and \dfrac{5}{6} as \dfrac{10}{12}, and then we simply subtract the numerators. This gives \dfrac{3}{12} - \dfrac{10}{12} = \dfrac{3 - 10}{12}.

Now, we work out 3 - 10 using a number line:

So, we get \dfrac{3 - 10}{12} = \dfrac{-7}{12} = -\dfrac{7}{12}.

FLAG

Calculate the value of $\dfrac{1}{5}-\dfrac{1}{2}.$

a
$\dfrac{1}{10}$
b
$-\dfrac{3}{5}$
c
$\dfrac{2}{5}$
d
$-\dfrac{3}{10}$
e
$-\dfrac{7}{10}$

Calculate the value of $\dfrac{1}{6}-\dfrac{3}{8}.$

a
$-\dfrac{7}{48}$
b
$-\dfrac{5}{24}$
c
$-\dfrac{7}{24}$
d
$\dfrac{11}{48}$
e
$-\dfrac{5}{12}$

Find the value of \dfrac{1}{3} - 2\,\dfrac{2}{3}.

EXPLANATION

First, we write 2 \, \dfrac{2}{3} as an improper fraction: 2 \,\dfrac{2}{3} = \dfrac{(2 \times 3) + 2}{3} = \dfrac{8}{3}

Since both fractions have the same denominators, we can combine them into one fraction, which gives \dfrac{1}{3} - \dfrac{8}{3} = \dfrac{1 - 8}{3}.

Now, we work out 1 - 8 using a number line:

So, we get \dfrac{1 - 8}{3} = \dfrac{-7}{3} = -\dfrac{7}{3}.

Finally, we write the resulting improper fraction as a mixed number:

-\dfrac{7}{3} = -2 \, \dfrac{1}{3}

FLAG

Find the value of $\dfrac{2}{5}-1\,\dfrac{1}{5}.$

a
$-1 \, \dfrac{2}{5}$
b
$-1 \, \dfrac{4}{5}$
c
$\dfrac{1}{5}$
d
$-\dfrac{4}{5}$
e
$-\dfrac{2}{5}$

Calculate the value of $-\dfrac{2}{3}-1\dfrac{5}{6}.$

a
$-\dfrac{2}{3}$
b
$-2 \, \dfrac{1}{2}$
c
$-1 \, \dfrac{2}{3}$
d
$-1 \, \dfrac{1}{2}$
e
$\dfrac{5}{6}$
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