Remember that every fraction represents a division: the numerator divided by the denominator.

For example, \dfrac{5}{3} = 5 \div 3.

We can use this idea to rewrite expressions containing fractions.

For example, suppose we want to rewrite the following expression:

\dfrac{5}{\color{red}3}\times {\color{blue}12}

Interpreting the fraction as division, we can write our expression as 5{\color{red}\;\div\; 3}{\color{blue}\;\times\; 12}.

Next, we use the fact that we can swap the order of multiplication and division. So, we can write an equivalent expression by switching the \color{red}\div\, 3 and the {\color{blue}\times\, 12}, as follows: 5{\color{blue}\;\times\; 12}{\color{red}\;\div\; 3}

Therefore,

\dfrac{5}{\color{red}3} \times {\color{blue}12} = 5{\color{blue}\;\times\; 12}{\color{red}\;\div\; 3}.

FLAG

What is missing from the statement below? 10 \times \dfrac{2}{5} = \bbox[2pt, border:1pt solid black]{\phantom{A}} \div \bbox[2pt, border:1pt solid black]{\phantom{A}} \times 2

EXPLANATION

Interpreting the fraction as division, we can write our expression as:

10 \times 2\div 5

We can write an equivalent expression by swapping the \times 2 and the \div 5\mathbin{:} \bbox[2pt, border:1pt solid black]{10} \div \bbox[2pt, border:1pt solid black]{5} \times 2 Therefore, the missing part is 10 \div 5.

FLAG

What is missing from the statement below?

\[ \dfrac{4}{3}\times 9 = 4 \times \bbox[2pt, border:1pt solid black]{\phantom{A}} \div \bbox[2pt, border:1pt solid black]{\phantom{A}} \]

a
$1 \div 3$
b
$9 \div 3$
c
$3 \div 9$
d
$3 \div 4$
e
$4 \div 9$

What is missing from the statement below? \[ 6 \times \dfrac{2}{3} = \bbox[2pt, border:1pt solid black]{\phantom{A}} \div \bbox[2pt, border:1pt solid black]{\phantom{A}} \times 2 \]

a
$6 \div 3$
b
$3 \div 6$
c
$3 \div 2$
d
$2 \div 6$
e
$2 \div 3$

Consider the expression \dfrac{5}{\color{red}3} \times {\color{blue}12}. By expressing the fraction as division, we have

5 {\color{red}\;\div\; 3} {\color{blue}\;\times\; 12},

and by swapping the {\color{red}\div\; 3} and the {\color{blue}\times\; 12}, we have

5 {\color{blue}\;\times\; 12}{\color{red}\;\div\; 3}.

Now, notice that we can rewrite the division {\color{blue}12} {\color{red}\;\div\; 3} as a new fraction \dfrac{\color{blue}12}{\color{red}3} to produce a new expression:

5\times \dfrac{\color{blue}12}{\color{red}3}

Therefore,

\dfrac{5}{\color{red}3} \times {\color{blue}12} = 5\times \dfrac{\color{blue}12}{\color{red}3}.

FLAG

What fraction is missing from the statement below?

7\div 5\times 20 =7\times \dfrac{\fbox{[math]\,\phantom{0}\,[/math]}}{\fbox{[math]\,\phantom{0}\,[/math]}}

EXPLANATION

We can write an equivalent expression by swapping the \div 5 and the \times 20\mathbin{:} 7 \times 20 \div 5

We can now interpret the division as a fraction: 7\times \dfrac{20}{5}

So, the missing fraction is \dfrac{20}{5}.

FLAG

What fraction is missing from the statement below?

\[ 2\div 3\times 9 =2\times \dfrac{\fbox{$\,\phantom{0}\,$}}{\fbox{$\,\phantom{0}\,$}} \]

a
$\dfrac{9}{2}$
b
$\dfrac{9}{3}$
c
$\dfrac{1}{3}$
d
$\dfrac{3}{9}$
e
$\dfrac{2}{9}$

What fraction is missing from the statement below?

\[ 3\div 2\times 4 = 3\times \dfrac{\fbox{$\,\phantom{0}\,$}}{\fbox{$\,\phantom{0}\,$}} \]

a
$\dfrac{1}{2}$
b
$\dfrac{1}{8}$
c
$\dfrac{4}{2}$
d
$\dfrac{2}{4}$
e
$\dfrac{8}{1}$

What fraction is missing from the statement below? \dfrac{5}{4}\times 8= 5 \times \dfrac{\bbox[2pt, border:1pt solid black]{\phantom{A}}}{\bbox[2pt, border:1pt solid black]{\phantom{A}}}

EXPLANATION

Interpreting the fraction as division, we can write our expression as:

5\div 4\times 8

We can write an equivalent expression by swapping the \div 4 and the \times 8{:}

5\times 8\div 4

Finally, we can write the 8\div 4 as a fraction:

5\times \dfrac{\bbox[2pt, border:1pt solid black]{8}}{\bbox[2pt, border:1pt solid black]{4}}

FLAG

What fraction is missing from the statement below? \[ \dfrac{5}{3}\times 6= 5 \times \dfrac{\bbox[2pt, border:1pt solid black]{\phantom{A}}}{\bbox[2pt, border:1pt solid black]{\phantom{A}}} \]

a
$\dfrac{3}{5}$
b
$\dfrac{3}{6}$
c
$\dfrac{6}{3}$
d
$\dfrac{5}{3}$
e
$\dfrac{1}{3}$

What fraction is missing from the statement below? \[ 18 \times \dfrac{1}{9} = \dfrac{\bbox[2pt, border:1pt solid black]{\phantom{A}}}{\bbox[2pt, border:1pt solid black]{\phantom{A}}} \times 1 \]

a
$\dfrac{9}{1}$
b
$\dfrac{1}{9}$
c
$\dfrac{9}{18}$
d
$\dfrac{18}{1}$
e
$\dfrac{18}{9}$

Let's evaluate the following expression:

\dfrac{5}{\color{red}3} \times {\color{blue}12}

First, by swapping the order of multiplication and division, we can rewrite our expression as

5\times \dfrac{\color{blue}12}{\color{red}3}.

Now, notice that {\color{red}3} is a factor of {\color{blue}{12}}, and

\dfrac{\color{blue}12}{\color{red}3} = {\color{blue}{12}} \div {\color{red}3} = 4.

Therefore, we can evaluate our entire expression as follows:

5\times \underbrace{\dfrac{\color{blue}12}{\color{red}3}}_{4} = 5 \times 4 = 20

FLAG

Evaluate 21 \times \dfrac{7}{3}.

EXPLANATION

Interpreting the fraction as division, we can write our expression as: 21\times 7\div 3

We can write an equivalent expression by swapping the \times 7 and the \div 3{:} 21 \div 3\times 7

Expressing the division as a fraction, we arrive at: \dfrac{21}{3}\times 7

We now solve: \underbrace{\dfrac{21}{3}}_{7}\times 7 = 7\times 7 = 49.

FLAG

$12 \times \dfrac{7}{4}=$

a
$32$
b
$18$
c
$24$
d
$16$
e
$21$

$\dfrac{3}{4}\times 36=$

a
$28$
b
$30$
c
$27$
d
$18$
e
$24$
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