We can plot a function by setting
To demonstrate, let's consider the function
where is any number taken from the set
First, we create a table containing the input values:
Given a value of we can find the corresponding -value by substituting into the formula For example,
if then
if then
Continuing in the same way, we get the following values:
Finally, we plot these pairs in the -plane:
We don't connect the points since is defined only for values of contained within the set
Let's now take a look at an example where is unrestricted.
What is the graph of where
Recall that the graph of is a straight line, and two distinct points can determine any straight line.
So, given any two distinct values of we can find the corresponding -values by substituting into the formula For example,
if then which gives the point and
if then which gives the point
Finally, we plot these pairs in the -plane and draw a line through them. This gives the following graph.
Which of the following shows the graph of $y=f(x),$ where $f(x) = 1+2x$ and $x$ is any number taken from the set $\{0,1,2,3\}?$
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a
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b
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c
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d
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e
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Which of the following is the graph of $y=f(x),$ where $f(x) = 1-2x?$
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a
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b
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c
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d
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e
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Consider the function shown below.
We can determine the values of this function at particular points by reading them off its graph.
Since the graph passes through the point we know that
Since the graph passes through the point we know that
Since the graph passes through the point we know that
Notice that the point is shown with an empty circle. This means that the function is undefined at the point where
The function is shown above. Calculate
We can find the necessary function values using the graph.
From the graph, we note the following:
When we have So,
When the function is undefined because the function has an open circle at this point.
Therefore, since is undefined, the sum is undefined too.
The function $y = f(x)$ is given by the graph above. Calculate $f(-3)+f(-1).$
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a
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$-4$ |
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b
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$-1$ |
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c
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Undefined |
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d
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$0$ |
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e
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$3$ |
The function $y = f(x)$ is shown above. Calculate $f(-1) + f(2).$
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a
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$5$ |
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b
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$0$ |
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c
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$-2$ |
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d
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$-4$ |
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e
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Undefined |