As we've seen, the cosine and sine ratios for acute angles can be defined in the following ways:
Using a right triangle. If is an acute angle in a right triangle, then
Using the unit circle. If is a central angle made by a point on the unit circle in the first quadrant, then
We can't define trigonometric ratios for non-acute angles using right triangles because a right triangle can't have angles larger than However, we can extend these ratios for non-acute angles using unit circles.
To do that, let's consider the unit circle with a central angle in any quadrant, measured in the usual way.
We define the sine and cosine of as follows:
In other words,
the cosine of is defined to be equal to the -coordinate of and
the sine of is defined to be equal to the -coordinate of
This way, our trigonometric ratios make sense for any angle, even if this angle is larger than
The diagram above shows a unit circle. Given that the -coordinate of the point is what is the value of
Any point on the unit circle is related to the central angle as follows:
We're given that at the point Therefore, we have
The diagram above shows a unit circle. Given that the $y$-coordinate of the point $P$ is $-0.75,$ which of the following is correct?
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a
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$\sin\theta = 0.15$ |
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b
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$\cos\theta = 0.15$ |
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c
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$\cos\theta = -0.75$ |
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d
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$\sin\theta = 0.75$ |
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e
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$\sin\theta = -0.75$ |
The diagram above shows a unit circle. Given that the $x$-coordinate of the point $P$ is $0.55,$ which of the following is correct?
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a
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$\cos\theta = -0.55$ |
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b
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$\cos\theta = 0.55$ |
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c
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$\sin\theta = 0.55$ |
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d
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$\sin\theta = 0.45$ |
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e
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$\cos\theta = 0.45$ |
We can use reference angles to evaluate trigonometric ratios for angles outside the first quadrant.
To demonstrate, let's determine the value of corresponding to the -coordinate of the point on the unit circle, as shown below.
The reference angle for is Let's add this to our diagram.
Let be the image of under a reflection across the -axis. This gives a pair of congruent angles of measure as shown.
According to the definition, is the -coordinate of the point But this is the same as the -coordinate of the point taken with the opposite sign.
The -coordinate of equals the cosine of the reference angle. Therefore, we conclude that
So, we simplified the evaluation of by evaluating the cosine of the corresponding reference angle with an additional sign adjustment for the final result.
We can use a similar argument to show that, since we have
In this case, we do NOT change the sign because the -coordinates of and are equal.
We can calculate a trigonometric ratio of any angle by finding the ratio of the corresponding reference angle and adjusting the sign depending on which quadrant our angle lies in.
To do this, we perform the following steps:
Find the reference angle
Calculate the value of the ratio for
Determine whether the resulting ratio is positive or negative.
We must do the last step because the ratio for will always be nonnegative, but the ratio for may not be.
But how do we determine whether the ratio for is positive or negative? This depends on the trigonometric ratio and which quadrant the angle is in.
To help us remember when various trigonometric ratios are positive, we use the mnemonic "All Students Take Calculus."
All of the trigonometric ratios are positive in quadrant I
Sine (and only sine) is positive in quadrant II
Tangent (and only tangent) is positive in quadrant III
Cosine (and only cosine) is positive in quadrant IV
We can represent this in a so-called CAST diagram, shown below.
For example, let's consider
Step 1: Since is the nd quadrant, the reference angle is
Step 2: The given ratio is and therefore we're interested in
Step 3: The ratio must be positive because the sine ratio is always positive in the nd quadrant. Therefore,
Let's see another example.
What is expressed in terms of a reference angle?
To express in terms of we follow three steps:
Find its reference angle
Calculate the value of the function for
Determine whether the resulting value is positive or negative.
First, let's draw the angle in the coordinate plane (CAST diagram):
Step 1: Since is in the th quadrant, the reference angle is
Step 2: The given ratio is and therefore we're interested in
Step 3: The ratio must be negative because the sine ratio is always negative in the th quadrant. Therefore,
What is $\sin 175^\circ$ expressed in terms of a reference angle?
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a
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$\sin 185^\circ$ |
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b
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$-\sin 5^\circ$ |
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c
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$\cos 185^\circ$ |
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d
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$\sin 355^\circ$ |
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e
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$\sin 5^\circ$ |
What is $\sin 320^\circ$ expressed in terms of a reference angle?
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a
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$-\sin 320^\circ$ |
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b
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$-\cos 320^\circ$ |
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c
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$-\sin 40^\circ$ |
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d
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$\sin 40^\circ$ |
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e
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$\cos 50^\circ$ |
What is expressed in terms of a reference angle?
To express in terms of we follow three steps:
Find its reference angle
Calculate the value of the function for
Determine whether the resulting value is positive or negative.
First, let's draw the angle in the coordinate plane (CAST diagram):
Step 1: Since is in the th quadrant, the reference angle is
Step 2: The given ratio is and therefore we're interested in
Step 3: The ratio must be positive because the cosine ratio is always positive in the th quadrant. Therefore,
What is $\cos 300^\circ$ expressed in terms of a reference angle?
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a
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$-\cos 60^\circ$ |
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b
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$-\sin 60^\circ$ |
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c
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$\cos 300^\circ$ |
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d
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$\cos 60^\circ$ |
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e
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$\sin 60^\circ$ |
What is $\cos 250^\circ$ expressed in terms of a reference angle?
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a
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$\cos 250^\circ$ |
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b
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$\cos 70^\circ$ |
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c
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$\sin 70^\circ$ |
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d
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$-\sin 70^\circ$ |
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e
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$-\cos 70^\circ$ |
What is expressed in terms of a reference angle?
To express in terms of we follow three steps:
Find its reference angle
Calculate the value of the function for
Determine whether the resulting value is positive or negative.
First, let's draw the angle in the coordinate plane (CAST diagram):
Step 1: Since is in the nd quadrant, the reference angle is
Step 2: The given ratio is , and therefore we're interested in
Step 3: The ratio must be negative because the tangent ratio is always negative in the nd quadrant. Therefore,
What is $\tan 235^\circ$ expressed in terms of a reference angle?
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a
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$\tan{55^\circ}$ |
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b
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$\tan{35^\circ}$ |
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c
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$-\tan{55^\circ}$ |
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d
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$-\tan{235^\circ}$ |
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e
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$-\tan{125^\circ}$ |
What is $\tan 325^\circ$ expressed in terms of a reference angle?
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a
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$-\tan{55^\circ}$ |
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b
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$-\tan{325^\circ}$ |
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c
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$\tan{35^\circ}$ |
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d
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$-\tan{35^\circ}$ |
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e
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$\tan{55^\circ}$ |