To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operations inside the parentheses:

\begin{align} 6\times (7-4) &=6\times({\color{blue}7-4})\\[5pt] &=6\times{\color{blue}3}. \end{align}

Now, we multiply:

\begin{align} 6\times 3 &= 18. \end{align}

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operations inside the parentheses from left to right:

\begin{align} (3+2)\times (3-1) &=({\color{blue}3+2})\times(3-1) \\[5pt] &={\color{blue}5}\times(3-1)\\[5pt] &=5\times({\color{red}3-1})\\[5pt] &=5\times{\color{red}2} \end{align}

Now, we multiply:

\begin{align} 5\times 2 &= 10. \end{align}

First, we calculate the expression inside the parentheses following the order of operations: \begin{align} 8 - 12\div 3 &=8-{\color{blue}12\div 3} \\[5pt] &=8-{\color{blue}4} \\[5pt] &={\color{red}4}. \end{align}

Next, we multiply: \begin{align} (8 - 12\div 3)\times 6 &=\underbrace{(8 - 12\div 3)}_{{\color{red}4}}\times 6\\[5pt] &= {\color{red}4}\times 6\\[5pt] &=\bbox[3pt,Gainsboro]{\color{blue}24}. \end{align}

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operation inside the inner parentheses:

\begin{align} [(3+4) \times 3] - 5 &=[({\color{blue}3+4}) \times 3] - 5 \\[5pt] &=[{\color{blue}7} \times 3] - 5 \end{align}

Next, we perform the operation inside the square brackets:

\begin{align} [7 \times 3] - 5 &= [{\color{red}7 \times 3}] - 5 \\[5pt] &= {\color{red}21} - 5 \end{align}

Finally, we subtract:

\[ 21 - 5 = 16 \]

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operation inside the inner parentheses: \begin{align} [30 \div (8 - 2)] \times 4 &=[30 \div ({\color{blue}8 - 2})] \times 4 \\[5pt] &=[30 \div {\color{blue}6}] \times 4 \end{align}

Next, we perform the operation inside the square brackets: \begin{align} [30 \div 6] \times 4 &= [{\color{red}30 \div 6}] \times 4\\[5pt] &= {\color{red}5} \times 4 \end{align}

Finally, we multiply: \[ 5 \times 4 = 20 \]

Therefore, $[30 \div (8 - 2)] \times 4 = \bbox[3pt,Gainsboro]{\color{blue}20}.$

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operation inside the inner parentheses: \begin{align} 30- [ (8+3)\times 2]&=30- [({\color{blue}8+3})\times 2]\\[5pt] &=30- [ {\color{blue}11}\times 2] \end{align}

Next, we perform the operation inside the square brackets: \begin{align} 30- [11\times 2] &=30- [{\color{red}11\times 2}] \\[5pt] &= 30- {\color{red}22} \end{align}

Finally, we subtract: \[ 30-22= 8 \]

Therefore, $30- [ (8+3)\times 2] = \bbox[3pt,Gainsboro]{\color{blue}8}.$

To evaluate the given expression, we must follow the order of operations with parentheses.

Therefore, we should start with the operation that's inside the most inner parentheses:

\[\{3+[({\color{blue}{22+3}})\div 5 +6\times 2]\}\div 4\]

So we should calculate ${\color{blue}{22+3}}$ first.

To evaluate the given expression, we must follow the order of operations with parentheses.

Therefore, we should start with the operation that's inside the most inner parentheses:

\[ \{1 - 4 \times [18 \div 3({\color{blue}2 + 4})] \} + 9 \]

So we should calculate ${\color{blue}{2 + 4}}$ first.

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operation inside the inner parentheses:

\begin{align} \{ [(1 \times 2) + 3] - 1\} \div 2 & = \{ [({\color{blue}{1 \times 2}}) + 3] - 1\} \div 2\\[5pt] & = \{ [{\color{blue}{2}} + 3] - 1\} \div 2 \\ \end{align}

Next, we perform the operation inside the square brackets:

\begin{align} \{ [2 + 3] - 1\} \div 2 & = \{ [{\color{red}{2 + 3}}] - 1\} \div 2\\[5pt] & = \{ {\color{red}{5}} - 1\} \div 2 \end{align}

Next, we perform the operation inside the braces:

\begin{align} \{5 - 1\} \div 2&=\{{\color{magenta}5 - 1}\}\div 2\\[5pt] &= {\color{magenta}4} \div 2 \end{align}

Finally, we divide:

\[ 4 \div 2 = 2 \]

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operation inside the inner parentheses: \begin{align} \{5 + [18 - (4 \times 2)] \} \div 3 & = \{5 + [18 - ({\color{blue}{4 \times 2}})] \} \div 3 \\[5pt] & = \{5 + [18 - {\color{blue}{8}}] \} \div 3 \end{align}

Next, we perform the operation inside the square brackets: \begin{align} \{5 + [18 - 8] \} \div 3 & = \{5 + [{\color{red}{18 - 8}}] \} \div 3\\[5pt] & = \{5 + {\color{red}{10}} \} \div 3 \end{align}

Next, we perform the operation inside the braces: \begin{align} \{5 + 10 \} \div 3 & = \{{\color{magenta}5+ 10}\} \div 3\\[5pt] &= {\color{magenta}15} \div 3 \end{align}

Finally, we divide: \[ 15 \div 3 = 5 \]

Therefore, $\{5 + [18 - (4 \times 2)] \} \div 3 = \bbox[3pt,Gainsboro]{\color{blue}5}.$

To evaluate the given expression, we follow the order of operations with parentheses.

First, we perform the operation inside the inner parentheses: \begin{align} 7\times\{15\div [9-(1+3)] \} & = 7\times \{15\div [9-({\color{blue}{1+3}})]\}\\[3pt] & =7\times\{15\div [9-{\color{blue}{4}}]\} \end{align}

Next, we perform the operation inside the square brackets: \begin{align} 7\times \{15\div [9-4]\} & =7\times \{15\div [{\color{red}{9-4}} ]\}\\[3pt] & =7\times \{15\div {\color{red}{5}} \} \end{align}

Next, we perform the operation inside the braces: \begin{align} 7\times \{15\div 5\} & = 7\times \{{\color{magenta}15\div 5}\}\\[3pt] &= 7\times {\color{magenta}3} \end{align}

Finally, we multiply: \[ 7\times 3 = 21 \]

Therefore, $7\times\{15\div [9-(1+3)] \} = \bbox[3pt,Gainsboro]{\color{blue}21}.$