We can use the standard algorithm to divide decimals by whole numbers.
To illustrate, let's compute
First, we write down the problem using long division notation, keeping the decimal point in the dividend:
We also bring the decimal point up into the quotient, placing it directly above the decimal point in the dividend:
Now, we carry out the long division process as usual:
Therefore,
Note: The "standard algorithm" is the same as "long division." The two phrases can be used interchangeably.
What is
We will use the standard algorithm.
First, we write down the problem using long division notation, keeping the decimal point in the dividend:
We also bring the decimal point up into the quotient, placing it directly above the decimal point in the dividend:
Now, we carry out the long division process as usual:
Therefore,
What is $76.5 \div 5?$
a
|
$15.3$ |
b
|
$15.1$ |
c
|
$15.5$ |
d
|
$15.7$ |
e
|
$15.8$ |
What is $9.6 \div 8?$
a
|
$1.4$ |
b
|
$1.1$ |
c
|
$1.7$ |
d
|
$1.2$ |
e
|
$1.3$ |
To make servings of ice cream, Rita used ounces of cocoa powder. How much cocoa powder did she use for each serving?
To determine the amount of cocoa powder Rita used to make each serving, we need to divide by To do this, we can use the standard algorithm.
First, we write down the problem using long division notation, keeping the decimal point in the dividend:
We also bring the decimal point up into the quotient, placing it directly above the decimal point in the dividend:
Now, we carry out the long division process as usual:
Therefore,
We conclude that Rita used ounces of cocoa powder to make each serving of ice cream.
A store owner evenly distributed $71.5$ pounds of salmon into $5$ refrigerators. How much salmon did he put into each refrigerator?
a
|
$14.5$ pounds |
b
|
$14.7$ pounds |
c
|
$11.9$ pounds |
d
|
$14.3$ pounds |
e
|
$13.9$ pounds |
Albert cut a $5.6$-foot piece of wire into $4$ pieces of equal length. How long is each piece?
a
|
$0.9$ feet |
b
|
$1.9$ feet |
c
|
$1.4$ feet |
d
|
$1.6$ feet |
e
|
$1.8$ feet |
We can also use the standard algorithm to divide decimals by other decimals. The only difference is that we first need to find an equivalent division problem where the divisor is a whole number.
To illustrate, let's compute First, we write this division problem as a fraction:
Then, we multiply the numerator and denominator by so that we get a whole number in the denominator:
Now we see that the division problem is equivalent to We can compute this using long division as usual:
From the long division, we find that so we conclude that
We can write this division problem as a fraction, as follows:
Multiplying the numerator and denominator by we get a whole number in the denominator:
Now we see that the division problem is equivalent to We can compute this using long division as usual:
From the long division, we find that so we conclude that
$8.19 \div 0.7=$
a
|
$11.5$ |
b
|
$11.6$ |
c
|
$11.9$ |
d
|
$11.7$ |
e
|
$11.3$ |
$0.92 \div 0.4=$
a
|
$2.2$ |
b
|
$2.3$ |
c
|
$2.5$ |
d
|
$2.4$ |
e
|
$2.1$ |
What is
We can write this division problem as a fraction, as follows:
Multiplying the numerator and denominator by we get a whole number in the denominator:
Now we see that the division problem is equivalent to We can compute this using the standard algorithm:
From the long division, we find that so we conclude that
What is $7.563 \div 0.03?$
a
|
$252.3$ |
b
|
$252.5$ |
c
|
$252.2$ |
d
|
$252.4$ |
e
|
$252.1$ |
What is $2.823 \div 0.04?$
a
|
$70.575$ |
b
|
$707.05$ |
c
|
$705.75$ |
d
|
$70.705$ |
e
|
$70.75$ |