We can use place value to add two-digit whole numbers easily.

As an example, let's find the following sum:

24+35

First, we line up our numbers (ones over ones and tens over tens):

tens ones
\color{red}2 \color{blue}4
\color{red}3 \color{blue}5

Next, we proceed by adding the numbers in each place value (from right to left) and writing the results below:

Step 1. Adding the ones, we get {\color{blue}4} + {\color{blue}5} = {\color{blue}9}{:}

tens ones
\color{red}2 \color{blue}4
\color{red}3 \color{blue}5
\color{blue}9

Step 2. Adding the tens, we get {\color{red}2} + {\color{red}3} = {\color{red}5}{:}

tens ones
\color{red}2 \color{blue}4
\color{red}3 \color{blue}5
\color{red}5 \color{blue}9

Therefore, we conclude that

24+35 = 59.

FLAG

Drawing place value charts each time we want to add a pair of numbers isn't very convenient. For this reason, we usually follow a simplified process called the standard algorithm.

Let's once again consider the following sum:

24+35

First, we line up our numbers as follows: (ones over ones, and tens over tens):

\begin{array}{cccccccc} & & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 4 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! \!\!\!\! \end{array}

Notice that we've also drawn a horizontal line. This is where we'll write our answer.

Next, we proceed by adding the numbers in each place value (from right to left):

Step 1. Adding the ones, we get {\color{blue}4} + {\color{blue}5} = {\color{blue}9}{:}

\begin{array}{cccccccc} & & \!\!\!\! 2 \!\!\!\!& \!\!\!\! {\color{blue}4} \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! {\color{blue}5} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}9} \!\!\!\! \end{array}

Step 2. Adding the tens, we get {\color{blue}2} + {\color{blue}3} = {\color{blue}5}{:}

\begin{array}{cccccccc} & & \!\!\!\! {\color{blue}2} \!\!\!\!& \!\!\!\! 4 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! {\color{blue}3} \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}5} \!\!\!\!& \!\!\!\! 9 \!\!\!\! \end{array}

Therefore,

24 + 35 = 59.

FLAG

Robert weighs 37 pounds, and Milly weighs 41 pounds. What is the combined weight of these two children?

EXPLANATION

To find the combined weight, we need to calculate the value of

37+41.

First, we line up our numbers (ones over ones and tens over tens):

\begin{array}{cccccccc} & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 4 \!\!\!\!& \!\!\!\! 1 \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! \!\!\!\! \end{array}

Next, we proceed by adding the numbers in each place value (from right to left):

Step 1. Adding the ones, {\color{blue}7} + {\color{blue}1} = {\color{blue}8}{:}

\begin{array}{cccccccc} & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! {\color{blue}7} \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 4 \!\!\!\!& \!\!\!\! {\color{blue}1} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}8} \!\!\!\! \end{array}

Step 2. Adding the tens, {\color{blue}3 } + {\color{blue}4} = {\color{blue}7}{:}

\begin{array}{cccccccc} & & \!\!\!\! {\color{blue}3} \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! {\color{blue}4} \!\!\!\!& \!\!\!\! 1 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}7} \!\!\!\!& \!\!\!\! 8 \!\!\!\! \end{array}

Therefore, 37 + 41 = 78.

So, the combined weight of the children is 78 pounds.

FLAG

$41+35 =$

a
$70$
b
$92$
c
$76$
d
$80$
e
$86$

$26 + 62 =$

a
b
c
d
e

Mary bought some candy for her daughter's birthday party. She bought $35$ mint candies and $41$ chocolate candies. How many candies did she buy altogether?

a
$76$ candies
b
$126$ candies
c
$66$ candies
d
$46$ candies
e
$74$ candies

Let's now calculate the following sum using place value charts:

37+26

First, we line up our numbers (ones over ones, and tens over tens), as before:

tens ones
\color{red}3 \color{blue}7
\color{red}2 \color{blue}6

Next, we proceed by adding the numbers in each place value (from right to left):

Step 1. Adding the ones, we get {\color{blue}7} + {\color{blue}6} = {\color{red}1}{\color{blue}3}.

Now, notice that

{\color{red}1}{\color{blue}3} = \textrm{[math]\color{red}1[/math] ten} + \textrm{[math]\color{blue}3[/math] ones}.

So, we write \color{blue}3 below the ones and carry \color{red}1 to the tens. Let's write this additional \color{red}1 over the tens column.

\color{red}1
tens ones
\color{red}3 \color{blue}7
\color{red}2 \color{blue}6
\color{blue}3

Step 2. Adding the tens, we get {\color{red}1} + {\color{red}3} + {\color{red}2} = {\color{red}6} (notice that we also add the \color{red}1 carried from the previous step):

\color{red}1
tens ones
\color{red}3 \color{blue}7
\color{red}2 \color{blue}6
\color{red}6 \color{blue}3

Therefore,

37+26 = 63.

Let's now solve the same problem using the standard algorithm.

FLAG

Once again, we consider the following sum:

37+26

To use the standard algorithm, we first line up our numbers (ones over ones, and tens over tens):

\begin{array}{cccccccc} & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 2 \!\!\!\!& \!\!\!\! 6 \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! \!\!\!\! \end{array}

Next, we proceed by adding the numbers in each place value (from right to left):

Step 1. Adding the ones, we get {\color{blue}7} + {\color{blue}6} = {\color{red}1}{\color{blue}3}. We write {\color{blue}3} below the ones and carry {\color{red}1} to the tens:

\begin{array}{cccccccc} & & \!\!\!\! {\color{red}1} \!\!\!\! & \\ & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! {\color{blue}7} \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 2 \!\!\!\!& \!\!\!\! {\color{blue}6} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}3} \!\!\!\! \end{array}

Step 2. Adding the tens, we get {\color{blue}1} + {\color{blue}3} + {\color{blue}2} = {\color{blue}6}{:}

\begin{array}{cccccccc} & & \!\!\!\! {\color{blue}1} \!\!\!\! & \\ & & \!\!\!\! {\color{blue}3} \!\!\!\!& \!\!\!\! 7 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! {\color{blue}2} \!\!\!\!& \!\!\!\! 6 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}6} \!\!\!\!& \!\!\!\! 3 \!\!\!\! \end{array}

Therefore,

37 + 26 = 63.

FLAG

The regular time of a particular soccer game lasted 92 minutes, and extra time lasted 33 minutes. How long did the game last in total?

EXPLANATION

To find the combined time, we need to calculate the value of

92 + 33.

First, we line up our numbers (ones over ones and tens over tens):

\begin{array}{cccccccc} & & \!\!\!\! 9 \!\!\!\!& \!\!\!\! 2 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! \!\!\!\! \end{array}

Next, we proceed by adding the numbers in each place value (from right to left):

Step 1. Adding the ones, {\color{blue}2} + {\color{blue}3} = {\color{blue}5}{:}

\begin{array}{cccccccc} & & \!\!\!\! 9 \!\!\!\!& \!\!\!\! {\color{blue}2} \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 3 \!\!\!\!& \!\!\!\! {\color{blue}3} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}5} \!\!\!\! \end{array}

Step 2. Adding the tens, {\color{blue}9} + {\color{blue}3} = {\color{red}1}{\color{blue}2}. We write {\color{blue}2} below the tens and carry {\color{red}1} to the hundreds:

\begin{array}{cccccccc} & \!\!\!\! {\color{red}1} \!\!\!\! & & \\ & & \!\!\!\! {\color{blue}9} \!\!\!\!& \!\!\!\! 2 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! {\color{blue}3} \!\!\!\!& \!\!\!\! 3 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}2} \!\!\!\!& \!\!\!\! 5 \!\!\!\! \end{array}

Step 3. Adding the hundreds, {\color{blue}1}+{\color{blue}0}+{\color{blue}0}={\color{blue}1}{:}

\begin{array}{cccccccc} & \!\!\!\! {\color{blue}1} \!\!\!\! & & \\ & \!\!\!\! {\color{blue}0} \!\!\!\! & \!\!\!\! 9 \!\!\!\!& \!\!\!\! 2 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & \!\!\!\! {\color{blue}0} \!\!\!\! & \!\!\!\! 3 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \\ \hline & \!\!\!\! {\color{blue}1} \!\!\!\!& \!\!\!\! 2 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \end{array}

Therefore, the game lasted 125 minutes.

FLAG

$47 + 29 =$

a
b
c
d
e

$93 + 74 =$

a
b
c
d
e

Peter has $18$ lemon candies while Angela has $25$ strawberry candies. Therefore, they have

a
b
c
d
e

What is 58+55?

EXPLANATION

First, we line up our numbers (ones over ones and tens over tens):

\begin{array}{cccccccc} & & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! \!\!\!\! \end{array}

Next, we proceed by adding the numbers in each place value (from right to left):

Step 1. Adding the ones, {\color{blue}8} + {\color{blue}5} = {\color{red}1}{\color{blue}3}. We write {\color{blue}3} below the ones and carry {\color{red}1} to the tens:

\begin{array}{cccccccc} & & \!\!\!\! {\color{red}1} \!\!\!\! & \\ & & \!\!\!\! 5 \!\!\!\!& \!\!\!\! {\color{blue}8} \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! 5 \!\!\!\!& \!\!\!\! {\color{blue}5} \!\!\!\! \\ \hline & & \!\!\!\! \!\!\!\!& \!\!\!\! {\color{blue}3} \!\!\!\! \end{array}

Step 2. Adding the tens, {\color{blue}1} + {\color{blue}5} + {\color{blue}5} = {\color{red}1}{\color{blue}1}. We write {\color{blue}1} below the tens and carry {\color{red}1} to the hundreds:

\begin{array}{cccccccc} & \!\!\!\! {\color{red}1} \!\!\!\! & \!\!\!\! {\color{blue}1} \!\!\!\! & \\ & & \!\!\!\! {\color{blue}5} \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & & \!\!\!\! {\color{blue}5} \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & & \!\!\!\! {\color{blue}1} \!\!\!\!& \!\!\!\! 3 \!\!\!\! \end{array}

Step 3. Notice that neither 58 nor 55 have a hundreds digit. Therefore, we place \color{red}0 in their hundreds places:

\begin{array}{cccccccc} & \!\!\!\! 1 \!\!\!\! & \!\!\!\! 1 \!\!\!\! & \\ & \!\!\!\! {\color{red}0} \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & \!\!\!\! {\color{red}0} \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & \!\!\!\! \!\!\!\!& \!\!\!\! 1 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \end{array}

Then, adding the hundreds, we get {\color{blue}1}+{\color{blue}0}+{\color{blue}0}={\color{blue}1}{:}

\begin{array}{cccccccc} & \!\!\!\! {\color{blue}1} \!\!\!\! & \!\!\!\! 1 \!\!\!\! & \\ & \!\!\!\! {\color{blue}0} \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 8 \!\!\!\! \\ \!\!\!\!+\!\!\!\! & \!\!\!\! {\color{blue}0} \!\!\!\! & \!\!\!\! 5 \!\!\!\!& \!\!\!\! 5 \!\!\!\! \\ \hline & \!\!\!\! {\color{blue}1} \!\!\!\!& \!\!\!\! 1 \!\!\!\!& \!\!\!\! 3 \!\!\!\! \end{array}

Therefore, 58 + 55 = 113.

FLAG

$94 + 48 =$

a
b
c
d
e

$17 + 94 =$

a
b
c
d
e

Dominic and his sister Margaret travel together to visit their parents. Dominic drives the car for $88$ miles, and then Margaret drives the remaining $79$ miles. Therefore, they drove a total of

a
b
c
d
e
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